2 math problems

<p>1) In a survey, 75 television viewers offered their opinions about program A and program B. Of those viewers, 18 likied neither program A nor program B. If 22 viewers liked program A only how many viewers liked program B only?</p>

<p>a) 3
b) 10
c) 15
d) 32
e) 35</p>

<p>the answer is b)10 but i just don't seem to grasp how to come to that answer =/</p>

<p>2)The average age of a certain group of 25 business managers is 40 years. If 5 additional managers are included in the group, then the average age of the 30 managers is 43 years. What is the average age of the 5 additional managers?</p>

<p>a) 50
b) 52
c) 55
d) 58
e) 60</p>

<p>the answer is d) 58, i still don't get why =/</p>

<p>thanks</p>

<p>For 2)
The sum of all the ages of the group with the additional managers:
30<em>43= 1290
The sum of the ages of the group initially:
25</em>40=1000
The sum of the ages of the 5 additional managers:
1290-1000= 290
The average of these 5:
290/5 = 58</p>

<h1>1 i get stuck at 18 - no like, 57 ppl total - like, 22 likes A and 35 likes A or A and B. dont know</h1>

<h1>2 average for 25 business managers = 40 years…</h1>

<p>1000 / 25 = 40 so assume the 25 business managers age adds up to 1000
now you age 5 ppl and you can assume they are all the same age
(1000 + 5x) / (25 + 5) = 43. do some algebra
and you end up with 58</p>

<p>1) Is this a CB problem? Either it’s not or you didn’t give enough information. You also need to know how many people liked both A and B in order to solve this.</p>