<p>Hey all! I'm just doing my last prep for the test tomorrow and have two math questions:</p>
<p>Long questions hence i have links to it:
1.<a href="http://oi56.tinypic.com/biq9nr.jpg%5B/url%5D">http://oi56.tinypic.com/biq9nr.jpg</a>
2.<a href="http://oi52.tinypic.com/mijpmb.jpg%5B/url%5D">http://oi52.tinypic.com/mijpmb.jpg</a></p>
<p>Thanks in advance to all that views and answers my question!!!</p>
<p>1) Is the answer (A)?
Since c,d are two different +ve integers,their squares would be different.
And the answer could be 0 only if c=d=1.
Hence,(a) is incorrect.</p>
<p>No the key says the answer is B. I thought it was A too.</p>
<p>15) The answer should be (A). If you move the 2 to the other side of the equation, you get c^2+d^2=2. No perfect squares added together equals 2.</p>
<p>EDIT: Apparently, the answer is (B) according the answer key?</p>
<ol>
<li><p>The answer is not A. 1^2+1^2=2. Just do trial and error and you’ll find B.</p></li>
<li><p>This one should read: If line m is a reflection of line l across the y-axis…</p></li>
</ol>
<p>This means that it will look exactly the same, but with a negative slope. The answer is A.</p>
<p>Can’t B be:0^2+2^2 -2=2</p>
<p>0 is not a positive integer. Correct answer is (B). Cannot be (A) because the question says “two positive integers”, do not have to be different, so</p>
<p>A. 1^2 + 1^2 - 2 = 0
B. Not possible.
C. 1^2 + 2^2 - 2 = 3
D. 2^2 + 2^2 - 2 = 6
E. 1^2 + 3^2 - 2 = 8</p>
<p>Oops. (A) is definitely the trick answer to #15. </p>
<p>And if you want to get technical about reflection about the y-axis, what that means is that f(x)=f(-x). Plug (-x) into (x) in the original equation to get the reflected line.</p>
