<p>ImageShack®</a>; - Online Photo and Video Hosting</p>
<p>ImageShack®</a>; - Online Photo and Video Hosting</p>
<p>is the first one 2 boys? you just multiply 1/3 by 6?</p>
<p>and I am lost for the second question :|</p>
<p>[ImageShack®</a>; - Online Photo and Video Hosting](<a href=“http://imageshack.us/photo/my-images/18/18196231.jpg/]ImageShack®”>ImageShack - Best place for all of your image hosting and image sharing needs) </p>
![http://imageshack.us/photo/my-images/18/18196231.jpg/]ImageShack®](http://imageshack.us/photo/my-images/18/18196231.jpg/%5DImageShack%C2%AE){kind=link}
<p>This one too please!</p>
<p>multiples of 3: 3, 6, …999 = 3<em>1, 3</em>2, 3<em>3, … 3</em>333 → so 333 of them
multiples of 4: 4, 8, … 1000 = 4<em>1, 4</em>2, …4*250 → so 250 of them
multiples of 3 & 4= multiples of 12: 12, 24, …996 → so 83 of them</p>
<p>multiples of 3 or 4 = 333 + 250 - 83 = 500 (C)</p>
<p>For the second problem: If the ratio of the radii is 1:3, then the ratio of the areas is 1^2:3^2 = 1:9, so the probability of a dart landing in the unshaded region is 1/9, which makes the probability of a dart NOT landing in the unshaded region (= landing in the shaded region) 1- 1/9 = 8/9. The expected value is (+$90)<em>(1/9)+(-$45)</em>(8/9)= -$30= loss of $30</p>
<p>cecilia87
By the way, what book are these questions from?</p>