<p>maximum of f(x) = 6
Find max of 3f(x-1)</p>
<p>Think of fuction with max value of 6… simply -x^2 + 6</p>
<p>therefore 3f(x-1) = 3(-x^2 + 5) = -3x^2 + 15</p>
<p>Now find max of -3x^2 + 15 = f(x)</p>
<p>f’(x) = -6x = 0 => x = 0
f(0) = [15]</p>
<p>I used a bit of calculus and I also got 15, so the answer to number 1.) is definitely 15. Your book is wrong.</p>