<li><p>What is the measure of one of hte larger angles of a parallelogram in the xy-plane that has vertices with coordinates (2,1),(5,1),(3,5),(6,5)?
ANSWER: 104 degrees</p></li>
<li><p>A line has parametric equations x=5+t and y=7+t, where t is the parameter. The slope of the line is
ANSWER: 1</p></li>
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<p>My question is, how do you solve these problems? Thanks in advance.</p>
<p>-etti</p>
<p>bump bump bump</p>
<ol>
<li><p>A(2,1), B(5,1), C(3,5), D(6,5). Find the slope of CA, using that find the angle and then find its supplement. angle = 76, supplement = 104.</p></li>
<li><p>The slope intercept form of the equation is y = x+2. Compare it with y=mx + c and you will see that m=1.(m=slope)</p></li>
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<p>;)</p>
<p>1) A (2,1), B (3,5), C (6,5), and D (5,1) --> Draw a perpendicular height from C down to D and name it E, the length of that would be (6,5) - (6,1) = 4. Then draw a horizontal base from E to D, the length of that would be 1. You can see that the triangle formed is a right triangle with base = 1 and leg = 4. Use Inverse Tan (4) = 76 degrees. The supplement of that is the large angle of the parallelogram = 180-76 = 104.</p>
<p>2) Simply eliminate T by plugging X - 5 into the Y equation. You then see that the coefficient next to X is 1.</p>
<p>i love you two</p>