<p>Trapezoidal sum buddy? Assuming A and B are values of X, each trapezoid would be (B-A)* 1/2(f(A)+f(B)).</p>
<p>And the maximum as most people have already pointed out is at t = 12. t = 9 is only a relative extrema, you must check both endpoints to determine the absolute maximum.</p>
<p>a) area under graph between 0 - 3
b) increasing because there is still more people going to the line then being accepted on the ride
c) t = 3 , 700 + intergral 0 - 3</p>
<p>d) forgot what i wrote and im to lazy to think!</p>
<p>And for Part C, it should be 23 - (∫(8→12) P(t)), rather than 112 - (∫(8→12) P(t)), seeing as E(t) represents the total number of entries at the given hours. Thus the answer should be 700 total entries left not yet processed by midnight.</p>
<p>Oh man; I had 16 entries. I forgot two things: (1) The hundred (1600 entries), and (2) I forgot to subtract that from 2300 (which would have gotten me 700 entries, the right answer).</p>
<p>So many stupid mistakes are costing me points… I better not lose the 5. >=(</p>
<p>I made sure to only work on parts that absolutely required a calculator during the time when a calculator was allowed. I then went back and finished the sections that didn’t need a calculator on the calculator section during the time when calculator were not allowed.</p>