<p>d). They’re being processed when P(t) prime = 0 and check the endpoints.
P’(t) = 0 –> t = 9.18, 10.81. Test these AND the end points, and you find that the
greatest at t = 12.</p>
<p>I did not do 1D that same way I thought each had to be seperately integrated since snow was being removed at different rates at different times according to the piecewise</p>
<p>Jersey, I hope you’re still around. You posted the following for 4C…</p>
<p>c) ∫(0→6) 3(y^2/4)^2 dy</p>
<p>Shouldn’t it be…</p>
<p>c) ∫(0→6) 3(y^2/4) * (y^2/4)</p>
<p>Since the formula for area of a rectangle is length * height, not height squared? Anyone? thanks</p>
<p>Also for 4b…</p>
<p>b) pi * Integral(0, 9) of ((2sqrt(x) - 7)^2 + (6-7) ^2)</p>
<p>Is this also correct? i did it weirdly, but it gives the same answer as jersey if evaluated I think (since you square everything, negatives go bye bye)…thanks.</p>
<p>But yeah, now I can’t remember whether I left it as (y^2/4) * (y^2/4) or (y^2/4)^2. Gah this is killing me, I need to know if I got a 5 or not! haha</p>
<p>Wait, they do mean the same if you square it first, right? I actually think they’re both the same now xD sorry, im really dumb.</p>
<p>I had a question about 6…here are my answers…</p>
<p>a) I had a bunch of incorrect crap written down. Then I got my brain together, and figured out what to do, and correctly figured it out y-2 = 8(x-1). The written crap won’t affect my score, will it? I forgot to cross it out.</p>
<p>b) plugged in 1.1 and got 2.8. BUT, I was dumb and said the tangent line was over estimate becasue if was concave up (instead of saying underestimate).</p>
<p>c) I only had time to separate the variables and integrate, but NOT calculate C.</p>
<p>How many points do you guys think I got for this? I’m guessing (hoping) for a 5/9? Thank you!!</p>