<p>Zn+2 has a higher ionization energy because as electrons decrease Z* increases and the elcetrons move closer to the nucleus so its harder to pull electrons away</p>
<p>ill do problem one</p>
<p>1)
a----ksp = [Ag+][Br-]
b---- 5e-13=x^2
[Ag+]=x=7.1e-7M</p>
<p>c—the same because the concentration at equilibrium will be constant
d—5/188=2.67e-2moles
7.1e-7=2.67e-2/x
x=37500 liters (this number seems huge lol)</p>
<p>e–i didn’t do a q (ugh) but i said that a precipitate would form. hopefully illg et a point</p>
<p>f–</p>
<p>(I) AgBr +NaI–> AgI + NaBr
Ag+ + I- –> AgI</p>
<p>(II) AgBr becuase of the electro negativity difference.</p>
<p>I don’t get 4a though lol
I’m sure you’re right or whatever I just don’t understand it I guess
I though since the base was more concentrated when you titrated it with a less concentrated acid even past the equivalence point…the solution would be more basic and therefore turn the indicator blue…am I wrong?</p>
<p>I think the answer is definitely Zn2+, If you agree that ionization energy increases the more electrons u take off, Zn already has 2 electrons gone, the effective nuclear charge on the now valence electrons are A LOT bigger than before</p>
<p>omgpie: OMG if what you just wrote down is right then I got bloody lucky on that question.</p>
<p>lol if you got what i got im a happy camper. hopefully we get at least 7s on the problem</p>
<p>^^ what? no It doesn’t lol
think about this Zn2+ is the same thing as nickel essentially
Zn has a full shell in the 3d level and nickel lacks 2 electrons in this level
pulling an electron from a full shell would be insanely hard…but removing one from nickel from its incomplete shell wouldn’t be as hard…Zn has a higher ionization energy lol</p>
<p>I missed part d for sure had no idea, but I somehow got all the other stuff you have down.</p>
<p>omgpie I think that big number is in milliliters.</p>
<p>I’m 100% positive I’m right because I memorized the periodic trends lol
as you go from left to right across the periodic table…ionization energy increases
I just used what I said above to justify the trend! haha</p>
<p>I didn’t get to finish my last FRQ answer, but I was in the general direction. I said something about the ions on the cathode being able to pull harder because the no3- was removed which uses force in numbers. Do you think they’ll know where I was going?</p>
<p>on your 1c I don’t get how the concentration will be the same…I understand it’s at equilibrium…however you have added 50 more mL of water to the 50 mL solution
since concentration is moles of solute/Liters of solution…you are essentially making this solution 100mL but leaving the moles of solute the same
therefore…the concentration, even after equilibrium is restored…will be less! you’ll have less moles of AgBr solid per liter of solution</p>
<p>That’s what my answer was lol</p>
<p>heres question 2</p>
<p>a) i said it would be -3.2 celcius. i took delta t = tf-ti</p>
<p>b) i think i did bad here. i said exothermic but i think it was endo. i mean it shows in the chart a positive h lol</p>
<p>c)
(i) q=gdeltats
=1236 joules</p>
<p>(ii)i got like 14.5 kj here. took q and divided by moles and divided by 1000 to get kj</p>
<p>d) G=H-TS (put the deltas in there). got like 70.1joules/mol kelvin</p>
<p>(e) 14-x/14=.11
x=12.46 kj/mol</p>
<p>(f)i siad increase because of the temperature going up?</p>
<p>bluejay youre wrong
1st ionization energy of Zn: 906.4 kJ mol-1
3rd ionization energy(of Zn which is the 1st ionization energy of Zn+2): 3832.6 kJ mol-1</p>
<p>YAY I totally said AgBr on 1f II because of electronegativity also! I made that up and wasn’t exactly sure if it would be something they’d go for lo
I’m happy then! :D</p>
<p>I agree with yejkim - Zn2+ would have a higher ionization energy.</p>
<p>who’s bluejay? are you talking to me??
how is that wrong? lol
3rd ionization energy of zn? why are you using that?
I can kind of see your logic here…hmmm lol
but ok let’s see here Zn2+ is the same thing as Ni because Zn2+ has 2 electrons less
the ionization energy of Ni is less than that of Zn…idk which is right! lol
I’m hoping if I am…I could still get points for my reason why…hahahaha</p>
<p>For 1b), I got a different answer. Tell me what you think of my logic.</p>
<p>AgBr—>Ag+ + Br-</p>
<p>[AgBr]= 0.05 L x (molar mass of AgBr)
= 0.05 L x (107+ 79)
= 9.3 M</p>
<p>Then, I used the Ice chart.</p>
<p>9.3 0 0
-x x x
9.3-x x x</p>
<p>5.0 x 10^-13= x^2/9.3-x</p>
<p>x= answer.</p>
<p>anybody do the same thing? Because why would they give us 50 mL of AgBr if it isn’t going to be used?</p>
<p>@yejkim1009: i agree completely – answer should be Zn^2+</p>
<p>i put change in temperature as 3.2 degrees, would that be wrong? lmao</p>
<p>Can somebody post a consolidated list as we go along?</p>