2010 AP Chemistry Free Response Discussion

<p>is 2)c.i negative or positive?</p>

<p>Did anyone else get a really big number for 1D? ~35000 liters???</p>

<p>1)f)ii) I put AgI would have the higher Ksp due to a lower lattice energy q1q2/r^2. I- is larger than Br-. More soluble due to weaker bonds, therefore higher Ksp.</p>

<p>2C i would be positive, since the reaction is endothermic</p>

<p>I got around 35000, but I thought that was in milliliters. I think i ended up saying 3.8 x 10^2 liters.</p>

<p>I got 35700 or 37500 liters as well.</p>

<p>38,000 L is the answer to 1d</p>

<p>1fii is AgBr due to Br’s greater electronegativity. (this makes it more polar than AgI, so it will be more soluble in water)</p>

<p>i got that but in liters. but im unsure of this one. i kinda felt i bombed on the 1st free response, but apparently not, looking at some other posts.</p>

<p>1D should be huge since for all intensive purposes AgBr is an insoluble substance.</p>

<p>… Doesn’t anyone disagree with what the first guy (NewAccount…?) said for 6d?
It literally asks to “Describe what happens in the salt bridge as the cell operates.” Wouldn’t the K+ exit and go to the cathode and NO3- would exit and go to the anode…?
Also, that one person who typed up #2 did a wrong calculation I think… For c i:
q= (c)(m)(Delta T)… no? So q= (4.2)(5.13)(-3.2)= -69 joules</p>

<p>@Nerdlings
k good. Also, was the mass for q=mcdT the mass of H2O + Urea?</p>

<p>2cii - Do you have to divide what you calculated for ci by the total mols (mols of h2o + urea)?</p>

<p>@Bgdz810
yes that’s what i put for the salt bridge question.</p>

<p>I got -69 joules as well.</p>

<p>^ yea because the heat of the solution changed and not the sample of urea</p>

<p>2ci) q= (4.2)(97.08)(3.2)
q= 1304.76 j
have to add mass of water with mass of urea for calorimetry calcs.</p>

<p>Well the problem is that they ask specifically for the heat of dissolution of urea.
Also, might’ve been a typo but don’t forget that it’s a negative value because of the negative delta T.</p>

<p>i got same as noob’s answer</p>

<p>They didn’t ask for the solution though. They asked for the urea.</p>

<p>which was 15.26 kj/mol after you converted the 1304 J to kj/mol</p>