<h1>what was the answer with the sin and cosine function? all i remember is the last two choices were 5pi/4 and 7pi/4. i got 7pi/4</h1>
<p>We were supposed to find the MINIMUM Velocity.</p>
<p>So I picked 135 degrees (7pi/4)
because at this point, both sine and cosine have the negative values of -sqrt(3)/2…</p>
<p>====EDIT: SORRY
225 DEGREES WOULD BE THE RIGHT ANSWER… 5PI/4</p>
<p>Did anyone get</p>
<p>e^2 for an integration problem? or any question for that matter?</p>
<p>I think it involved “h->0”</p>
<p>At 7pi/4, cos is positive, not negative. That’s why I thought it was 5pi/4.</p>
<p>Yep, that exact question was on a released practice exam actually</p>
<p>@pkim850</p>
<p>Ehrmmm, at that value, sin and cos have OPPOSITE values of root(2)/2. That was the correct answer, though! (I’m 99% sure, at least…)</p>
<p>@Neutrino</p>
<p>Oh yeah you’re right.
I hope I put 5pi/4
I knew how to do it…</p>
<p>I know that feel bro. Happens to me all the time. =/</p>
<p>I’m fairly sure that it was 7pi/4, because that was the value at which v(t) had the most negative value…I think it was something like sin(x)-cos(x), and had something to do with the value root(2)/2. Gahh, my brain is wiped</p>
<p>mada is right</p>
<p>@Fast, that’s what I did, 5pi/4 because it was in the 3rd quadrant.</p>
<p>Also, i saw someone say an answer was (0,e^3/2), i thinnnk i put (e^3/2, inf)</p>
<p>Also, what did yall do for the find the value of the temp at t=25; that caught me off guard. I did int from 24 to 25 v(t)dt and then added t(0) which was 55 to get about 55.2 or so.</p>
<p>Well all I remember is that when I had the acceleration set to 0, I got cosx = sinx. The zeroes of the acceleration function would be the maxima of the velocity function, and I got pi/4 and 5pi/4 as the zeroes.</p>
<p>Anyone remember the linear approximation question? It was on the non-calculator MC. Answer choice were like 2.8, 2.9, etc…</p>
<p>7pi/4 had the most negative value though</p>
<p>@mathisfun</p>
<p>int from 20 to 25 you mean?</p>
<p>anyone remember the limit question with the graph? as x approaches 2 from the right? i chose 2 but i think thats wrong</p>
<p>That doesn’t make sense to me. Does anyone remember the velocity function? I feel like it was cosx + sinx, but I’m not sure.</p>
<p>For the temp at 25 it was integral of 20 to 25 plus W(20)</p>
<p>Linear approximation was 2.9</p>
<p>For the limit as x approaches 2 on the right was 3??? Hard to remember…</p>
<p>I got cos(x) = -sin(x) as well.</p>
<p>Neutrino: yes I’m sure that was the velocity function
because</p>
<p>I got that cos(x) = -sin(x)…</p>
<p>For the one free response where you found the solution to the differential equation with the weight of the bird, i got what FastNeutrino got: B(t) = 100 - 80e^(-t/5). Just curious, how did you guys get ln(81) as the constant? I got -ln(80).</p>
<p>@pk, no i did write this on my test as well 1/5(int from 20 to 25)W’(t)dt + 55</p>
<p>and i did 24 to 25 because that gives you an approx of w(25)</p>
<p>idk, that one threw me offguard.</p>
<p>Also, what was the answer to the HA at 2 and -2?</p>