<p>Lol why is it that everyone else posts their answers before me. Its seems as if I’m copying the people who respond faster</p>
<p>someone want to make a google doc</p>
<p>@cindycray There is a Google doc that someone made: <a href=“AP Stats 2014 discussion”>https://docs.google.com/document/d/1a6ARXhpc5Sk-wbGNY5B2LOtO8boNaDmThq_p4o-rXHc/mobilebasic</a></p>
<p>If somebody got any questions, I can help. Even though I screwed up the last two parts of FRQ 6 and the Monday and Friday question, I’m not a complete dunce. </p>
<p>.</p>
<p>Are we allowed to talk about the multiple choice? Or naaah</p>
<p>We are not allowed to talk about the multiple choice questions. Additionally, there was someone who asked about the engine size or wheelbase question: The answer is engine size because it has a clear effect on the residuals, meaning it should be taken into account in the multiple regression, whereas wheelbase may have not had any influence at all by observing the very scattered plot.</p>
<p>wait yeah lets talk about multiple choice. everyone else is for other tests and college board wont find us. also, was it chi squared with 4 degrees of freedom or 99 degree</p>
<ol>
<li>There were 5 categories, which is used in calculating the degrees of freedom for chi squared, not sample size.</li>
</ol>
<p>This is what I all got, of course paraphrased (a lot):
- A) .7273 and .5522
B) Talking about how on campus generally had more people involved in extracurricular activities (went into more detail)…
C) High p value (greater than alpha of .05 if you wish), so fail to reject H0, elaborated more</p>
<ol>
<li><p>A) As everyone has been saying, (1/3)(1/4)(1/7)=.0119
B) Super low, doubtful by chance, so there could be a reason to doubt… However not impossible
C) Nope, Does not take into account how the second and third selection of the woman depends on the first section… Rolling die is independent</p></li>
<li><p>A)Found a z score of 1.90… The probability is .0284
B) Less likely… If there is an extreme case of absenses one day, taking a mean stabilizes it making it less likely for the mean amount to be greater than 140 than a single observation number of absenses to be greater than 140
C) .064… (2/5)^3</p></li>
<li><p>A) Median b/c extreme cases of income (like a millionaire or billionaire) doesnt completely shift that central representation… Median would be a better representation of center
B) Method 2… Avoid Voluntary response bias that is in method 1 (this bias would make the mean amount higher than the true mean bc people with high incomes are more likely to respond to the online survey)… Of course I elaborated more, but that was the main point for this part</p></li>
<li><p>Match pair difference of means t-test
Conditions: 1. Random sample, 2. Population distribution approx normal bc Dotplot doesnt have any extreme outliers or skewness, 3. Men/Women choosing independent, BUT dependent on the certain model (thus match pairs)
Showed my work and all… df=n-1=8-1=7
t=3.118, p value of .008448 < my alpha of .05
Conclusion: reject H0, elaborated more</p></li>
<li><p>A) Residual = y_actual - yhat… get yhat from the FCR equation… You should get .9550… To interpert it, all I said was that the actual FCR was .9550 off the predicted amount that the least squares regression line based on lengths gave you.
B) This is kinda trivial IMO… Not trying to be mean or anything, but common… Well actually I guess you had to do A right to get the first one… For the second one: it indicates that the least squares regression line did a good job predicting the actual FCR value… Basically the actual FCR was close to the predicted FCR
C) Graph 2 stronger than Graph 3… Both positive, linear, but again Graph 2 stronger… Of course, again, I elaborated more
D) Ok for this one Im going to make a seperate post.</p></li>
</ol>
<p>Ok for D)
I know a lot of you think that it is wheel base size since our teachers have deeply ingrained in us that no pattern in residuals = good linear fit… However, I thought this was an extreme ■■■■■ by collegeboard, these are not the same residual graphs our teachers told us about… I agree with arceusnormal and everyone else who said engine size…
This is because since engine size has a better linear relationship with the RESIDUALS FROM THE LIN REG OF FCR AND LENGTH (stupid collegeboard, tricky tricky). When coupled with the length lin reg, the engine size can predict the residual from a graph like graph II, which can then be added to the predicted amount from a graph like Graph 1, if that makes sense…</p>
<p>Oh, and btw, these are by no means the “correct” solutions, just my interpertations and solutions… Im a 5 hopeful :). Just ask any questions or have any disputes… All this being said… Nothing will change now… THeres no point in hoping or speculating… Lets all just wait till june or july (I forget when we get them)… I have to worry about 2 more APs haha, physics wont be too hard, I have to study a bit for APUSH
I hope everyone here gets what they want! </p>
<p><a href=“AP Stats 2014 discussion - Google Docs”>AP Stats 2014 discussion - Google Docs;
<p>we can discuss here guys</p>
<p>How is it that I sat for the exam but got completely different qs for the frq section? It was different from what was posted on college board as well.</p>
<p>Is it possible to get 0 points on a free response question? If so, how?</p>
<p>@shijurodhaz i got different questions as well. did anyone else get different questions too?</p>
<p>Just found out there is another form (form B) for students outside US, but I can’t find the questions anywhere.</p>
<p>I know this has already been stated, but the FRQs have been released already. Here’s the link to the page: <a href=“http://media.collegeboard.com/digitalServices/pdf/ap/ap14_frq_statistics.pdf”>http://media.collegeboard.com/digitalServices/pdf/ap/ap14_frq_statistics.pdf</a></p>
<p>guys the answer was graph 3 wheel base. my teacher said so</p>
<p>@hasaialak my stats teacher said it was graph 3 wheel base</p>