<p>Hey guys,
Could someone please solve these problems and tell me how to them?
<a href="http://i53.tinypic.com/seu1py.png%5B/IMG%5D">http://i53.tinypic.com/seu1py.png
</a>
thank you!</p>
<p>bump. please, desperately need help!</p>
<p>I can tell you how to solve 58.:</p>
<p>You have to substitute T with one of the given Matrices so that the given
equation is true.
Therefore you have to know how matrices multiplication works.
In this case you have a 2x2 matrix for T multiplied with a two dimensional vector.
You have to take the two LINES of the vector and have to multiply each LINE with each
column of the first line of the 2x2 matrix and add the results together to get the number for the first line after the equation. You do the same thing with the bottom line of the 2x2 matrix. It’s kinda hard to understand that so I just give you an example:</p>
<p>(2 3) x (2) = (2x2 + 3x1) = (7)
(0 1) (1) (2x0 + 1x1) (1)</p>
<p>So in ex 58. the vecor is (-3) and the result is supposed to be (5).
(5 ) (3)</p>
<p>-> So for T we are looking for something like (0 1) in the first line to get to the 5 in the result. And here you can already stop because only answer G is providing that.</p>
<p>I hope that helps.</p>
<p>These questions (except for the last one) are of the SAT II level.</p>
<h1>56.</h1>
<p>(sinA)^2 + (sinB)^2 = (sinA)^2 + (cosA)^2 = 1.</p>
<h1>58.</h1>
<p>Amad3us gave a good explanation; alignment of matrices and vectors is off, unfortunately.</p>
<h1>59.</h1>
<p>n!/(n-2)! = 1x2x3x…x(n-1)x(n) / (1x2x3x…x(n-2)) = (n-1)n = 30.
n=6
(n-1)! = 5! = 120.</p>
<h1>60 (?)</h1>
<p>Triangles AEB and DEC are similar.
CE/EA = DC/AB
10/4 = x/6
x = 15</p>
<p>thank you! </p>
<p>but i put G for #58. It’s wrong. The answer is K.</p>
<p>also, how does #59 work? thank you</p>