<p>I'm not going to write the problems out because they involve pictures.. so if you could take a look at them if you have the book, then that would be awesome :)</p>
<p>Section 5:
18.
20.</p>
<p>Section 8:
15.</p>
<p>Thanks in advance!</p>
<p>Which test are you referring to?</p>
<p>Oh wow. I’m dumb.
Haha.
Thanks.
It was test 9!</p>
<p>Section 5
18: For this one, it’d be nice to know the formula length of arc= n degrees/360degrees<em>circumference. It is given that there are 18 arcs of each length, so 18</em>2 +18b=45 <– (the circumference) Solve for b, and you get b=1/2. Referring back to the equation above: the degree,n, for each of the arcs of b is given by .5= n/360*45. Solve for n, and you get 4degrees, which is answer A.</p>
<ol>
<li>For this one, I made up my own values. I said the value of each of the five line segments was 2 and let’s call the halfpoint between A and C is X. Therefore, line segment AX=1. Since AD=2 and DX=1 we can find AX, which is root3. If you double the value of AX, you get AC, which is 2*root3, and since BD=2, the ratio of AC to BD= root3 to 1, which is answer B.</li>
</ol>
<p>What is BB?</p>
<p>Thanks pencil!
Any idea about the last problem? :D</p>
<p>Custard, BB stands for “blue book”
As in the official collegeboard SAT study guide.</p>
<p>All of the angles have their bases in the same plane. This makes it possible to compare them.</p>
<p>Angles XCY and XEY are equal. That eliminates them because you can only have one answer. </p>
<p>It is easy to see that XAY is smaller than XBY. Because XA is longer than XB, the angle is smaller.</p>
<p>That leaves XAY and XDY. It’s the same principal here: XD is longer than XA so it creates a smaller angle. </p>
<p>If you have a hard time seeing this, draw each angle in 2D and compare them side by side.</p>
<p>the question asks that which of the angle is least among <A , <B, <C , <D ,<E…</p>
<p>That angle will be least whose point of formation is the farthest. The farthest point amongst A,B,C,D &E is D.</p>
<p>So the smallest angle is <D = < XDY</p>