<p>In the figure above, the scale on e x-axis is different from the scale on the y-axis. If the area of ABC is 18 what is the value of k?</p>
<p>a. 3/10
b. 3/4
c. 6/5
d. 3/2
e. 3</p>
<h1>16 Page 535:</h1>
<p>If a + b is equal to 125 percent of 4b, what is the value of a/b?</p>
<h1>10 Page 549:</h1>
<p>A right circular cylinder with radius 5 and height 4 has volume v. In terms of v, what is the volume of a right circular cylinder with radius 5 and height 8?</p>
<p>a. v+4
b. 2v
c. 4v
d. 6v
e. 8v</p>
<h1>14 Page 550:</h1>
<p>If 0 < x < 1, which of the following statements must be true?</p>
<p>i. x^2>x^3
ii. x> x/2
iii. x>x^3</p>
<p>a. i only
b. ii only
c. i and ii only
d. i and iii only
e. i, ii, and iii</p>
<p>v=hr^2п
in the first cylinder h=4 ,and the volume is v.In the second cylider the h=2times the height of the first one,so the volume will be two times bigger ,so 2v</p>
<h1>14 Page 550:</h1>
<p>let x be 1/2
(1/2)^2 = 1/4 and (1/2)^3 =1/8 .1/4 >1/8 so statement I is correct</p>
<p>1/2/2=1/4
1/2 >1/4 ==>statement II is also correct </p>
<p>x^3= 1/8
1/2 >1/8 ==>statement III is correct ==> E </p>
<p>I am too lazy to open the BB and see the figure in problem #5 Page 531: ,so i hope someone else will help you ;)</p>
<p>A quick way to work on #16 would be to use the equation a+b=1.25(4b) which ends up as a+b=5b. After subtraction, only a=4b is left; and dividing b from both sides of the equation only leaves a/b equaling four.</p>
<p>Yoda, I've noticed you've been posting a few math problems and I was thinking if you are having trouble with them, maybe you could say a little about what the problem is? I say that because it seems like problems like #16 Page 535 and #10 Page 549 are fairly straightforward...</p>
<p>Well for number 16 I used the equation a+b=4b/1.25. You may be asking why and it is because I remebered from some problem on the ACT I did a while back that to find like 115% of a number you divide it by the decimal or something. very confusing, I know. That messed me up there.</p>
<p>The other one I just plugged in the stuff and solved it. Like I put in the stuff for the first cylinder and got 29. Then I did it with the height being 8 and got 33. 33-29=4 so I put v+4. </p>
<p>I see now where I went wrong. Sorry for seeming stupid it's just that some of these problems trick me. </p>
<p>I would very much appreciate it if someone could help me with the one with the diagram.</p>
<p>If you regard the triangle, then you have 18 = (1/2) B * H, where H = 4. (6-2 on the axis).
Therefore, B = 9. AC consisted of 3 mark distance, 5k - 2k = 3k. 9/3=3. --> E</p>