4 Questions on the December SAT Math

<p>1) That problem with yz>0 and xyz all odd, and what not that was all 3, right?</p>

<p>2) The one with 2 diamaters intersecting was 60 degrees, right?</p>

<p>3) This one seemed too easy. "If there are m minutes in h hours, what is h in terms of m?" I put m= 60h....but that seems too easy...</p>

<p>4) The one with a triangle and parallel lines was 76 degrees right?</p>

<p>m=h/60......</p>

<p>that was not all 3. It was only II, III because it said MUST. but although the I is true for one set up, it is not always true. since YZ can both be positive/neg</p>

<ol>
<li><p>60 deg</p></li>
<li><p>m = h/60</p></li>
<li><p>i got 120. but i may be thinking of the parallegoram one...?</p></li>
</ol>

<p>dang it ...i put m=60h...</p>

<p>1) I'm pretty sure the answer to that one was all three b/c yz does have to be greater than zero for the result to be negative, because it would then be multiplied by the lowest number, x, which would definitely have to be negative (they couldn't all be positive to get a negative result). Negative * positive = negative</p>

<p>2) Don't remember what I put for that one...</p>

<p>3) m=60h--if you have three hours, for example, then you multiply that by 60 to get the number of minutes...I don't see why people are saying h/60.</p>

<p>4) I think I got 110 for that, but I could be thinking of a different problem...</p>

<p>1) I put all 3
2) I was going to put 60...seriously, just omitted it though
3) m=60h
4) I remember 110, grid-in, right?</p>

<p>^ i think the reason they put h/60 because the question asks for m in terms of h...so.......600mintues in terms of h...is 6/600...wait does not even make sense....w/e i put m=60h</p>

<p>It was a grid-in but it was like a triangle, I don't think it could have been 110, it wasn't the parallelogram...it was like a triangle with lines in it thaty were parallel. It gave an angle of like 142 and 108.</p>

<p>I think the triangle one was 110. I remember that the supplement to my answer was 70, so...</p>

<p>Ok, and does anyone remember an answer with like rt( h^2 + 25) it was a trapezoid?</p>

<p>ok...this is getting too depressing for me....</p>

<p>"It gave an angle of like 142 and 108."</p>

<p>Then it wasn't the same one I got.</p>

<p>" rt( h^2 + 25) it was a trapezoid?"</p>

<p>I got that.</p>

<p>"600mintues in terms of h...is 6/600...wait does not even make sense....w/e i put m=60h"</p>

<p>Seriously...this wasn't a mind-shattering question. It was definitely m=60h.</p>

<p>If you have 1 hour...it is 60 minutes.
If you have 2 hours...it is 120 minutes.
Yay for you!</p>

<p>Glucose, I've gotten an 800 before so I'm no moron. The problem is, it was like number 13 on the test and that seemed way too easy to be number 13?</p>

<p>I've yet to find anyone who can remember that question too, ffs.</p>

<p>The answer to the trapezoid one was "sqrt(h^2 + 25)" I believe. H was the height of the trapezoid, and therefore the height of the triangle. THe top and bottom were lengths m and m+5, therefore the base of the triangle is 5. Use pythag theorem and you get my answer.</p>

<p>Glucose I got 110 as well. It was that problem that had a triangle resting on its side with two parallel lines cutting it?</p>

<p>yea.....it seemed way to easy for being 13...</p>

<p>Let's get the triangle one with parallel lines, no freaking way I'm the only one in the world to answer that question...</p>

<p>I never said you were a moron. I'm glad you got an 800, which means you really shouldn't care all too much. I looked at the question twice, but m=60h was the only answer that made any remote sense.</p>

<p>Ikir, did it give you angles of like 140 something and 108? That's the one I'm talking about, he's thinking it may be a different one... I remember copying the angle measurements into my calc after the whole test ended to ask you guys...</p>

<p>I'm not sure. List some of the problems you had on your version of the test. </p>

<p>I had a toothpick problem, bacteria problem, the "xyz is a negative odd integer" one, and the one with 2 diameters bisecting the circle.</p>