A calc question...an easy one

<p>So I was wondering how you would go about solving these types of problems, where they give you values for the derivatives and functions and such. Then tell you to solve for the equation thing they give you.</p>

<p>The table of values</p>

<p>X f(x) g(x) f'(x) g'(x)
0 1 1 5 3
1 3 -4 -2 -8</p>

<p>Then they ask to solve</p>

<p>g(f(x)) at x=0
5(f(x))-g(x) at x=1</p>

<p>I know the first has to do with the chain rule somehow...but I'm not sure. Could someone please help?</p>

<p>If I'm reading your table right, it lists that:</p>

<p>f(0) = 1
g(0) = 1
f'(0) = 5
g'(0) = 3
and
f(1) = 3
g(1) = -4
f'(1) = -2
g'(1) = -8</p>

<p>and asks for g ( f(x) ) when x = 0 first.</p>

<p>Plug in 0 for x to get:</p>

<p>g ( f(0) ). You already have the value of f(0) = 1. Plug this in.</p>

<p>g(1) = -4. That's the first answer, if I'm not mistaken.</p>

<p>For 5f(x) - g(x) at x = 1, plug in 1 for x.</p>

<p>5f(1) - g(1). You have the values of f(1) = 3 and g(1) = -4</p>

<p>5*3 - -4 = 15 + 4 = 19</p>

<p>I'd don't really know why you'd need the derivatives in this problem unless I am reading this wrong.</p>

<p>Well, I did put -4 for the first one, and it's wrong. I know you have to do a chain rule or something...but I don't exactly how.</p>

<p>And thanks</p>

<p>The way the question is written here, diamondbacker's solution is correct.</p>

<p>However, I'm pretty sure that the actual question, given the information at hand, is asking for you to find the derivative of g(f(x)) at x = 0 and the derivative of 5f(x) - g(x) at x = 1.</p>

<p>In which case, d/dx[g(f(x))] = g'(f(x))* f'(x). At x = 0, this is g'(f(0)) * f '(0) = g'(1)<em>f '(0) = -8</em>5 = -40.</p>

<p>Basically, when you're performing the Chain Rule, you start to take the derivative of g(f(x)) just as if it were g(x) [and since the derivative of g(x) = g'(x), start the derivative of g(f(x)) as g'(f(x))], and then compensate for the fact that your input into g(x) isn't x, it's f(x), by taking the derivative of that different piece, or in other words, multiplying by f '(x).</p>

<p>As for the second question, the derivative of 5f(x) - g(x) = 5f '(x) - g'(x). At x = 1, 5f '(1) - g'(1) = 5(-2) - (-8) = -10 + 8 = -2.</p>

<p>Oh alright, I understand. Thank you very much.</p>