<p>How many positive four-digit integers have 1 as their first digit and 2 or 5 as their last?
144
180
200
300
720</p>
<p>Thanks :)</p>
<p>i think the answer is 200 right?</p>
<p>1x10x10x2</p>
<hr>
<p>1= Must be a ‘1’ in the start, so only 1 choice from 0-9 (thousand)
10=Numbers can be reused, so 10 choices from 0-9, 10 numbers (hundreds)
10=Same as above
2=Last digit must be a 2 or 5, so 2 choices from 0-9 (units)</p>
<p>so 1x10x10x2=200.</p>
<p>hope its correct</p>
<p>^Kevin is correct.</p>
<p>Yes this is the correct answer…thank i very much</p>