<p>This is from Barrons. If i is a root of x^4 + 2x^3 - 3x^2 + 2x - 4=0, what are the real roots?</p>
<p>Use synthetic division to figure them out. They can be -4,-1,-2,2,1,4. Try em out.</p>
<p>I didn't get that. I used synthetic division for i. Then I used it for -i. That gives you x^2 + 2x - 4, which can't be factored. You can either find the real roots using the calculator or the quadratic formula. Either way you get -1 +/- square root of 5, or -3.2361 and 1.2361.</p>
<p>If you know i is a root, then -i must also be a root. (x-i)(x+i)=x^2+1. Do some division and use the quadratic formula.</p>
<p>hey thanks guys</p>
<p>for the math2c, how important is it to know trig concepts if i get a graphing calc? In the barrons, they ask questions like the function of f(x) = (Square root 3) (cosx ) + (sinx).</p>
<p>Now honestly i dont really advanced trig very well. Is it needed for the test or can i just graph it into the calc?</p>
<p>thanks</p>
<p>Also, out of 50 questions, about how many are advanced trig?</p>
<p>Is the answer -1 and -9? or what?</p>
<p>the answer is -1 +/- square root of 5.</p>
<p>Out of 50, about how many trig questions are this hard? "Solve sinx sinx 40 degrees - cosx cos 40 degress = 1/2 for all values of x such that 0 less than equal to x less than equal to 360?</p>
<p>use a calculator. some will most likely be integers and you can solve the non-integer roots after you factor out the ones you know using synthetic division in two seconds. Or just eliminate however many multiple choice answers the integer roots nullify and find the decimal approximations for the roots in the answers that are left. in most cases it'll be similar ones with different signs. In the end, it doesn't matter how or why you got the answer, just that it's right and that you did it as quickly as possible.</p>
<p>about how many trig questions are this hard? "Solve sinx sinx 40 degrees - cosx cos 40 degress = 1/2 for all values of x such that 0 less than equal to x less than equal to 360?</p>