<p>im pretty sure these types of questions appear on both but im taking BC,
No Calculator Q, I dont know why but my math teacher always pop up past questions for no apparent reason even though he knows that more than half the students are going to get it wrong, were on avg volume and he gave us a pop quiz and here is the question, indian teachers these days </p>
<p>lim x->0 (1/lnx)-(1/(x-1))
I know the ans (1/2) BECAUSE I JUST USED MY CALCULATOR but dont know how to get there
thanks for anybodys help
i dont think this q is hard but there is supposed to be some sort of trick to do this that will make the ans so F****** obvious.</p>
<p>Distribute the limit: (lim(x->0) (1/(ln x))) - (lim(y->0) (1/(y-1)))
The second limit evaluates trivially to -1, so this is equivalent to (lim(x->0) (1/(ln x))) + 1
Now, 1/(ln x) goes to negative infinity as x goes to 0. Therefore, the limit does not exist.</p>
<p>I have no idea how you got 1/2, but I’m almost completely sure it’s wrong.</p>
<p>Well first off, I think the limit can only be evaluated from the right, but I’m getting the answer to be 1, because 1/(lnx) approaches 0 as x approaches 0, so the 2nd term is what determines it, which I’m getting to be 1.</p>