ACT Question!!! Help Needed!

Test Preparation ACT Preparation
1

<p>Please explain everything in detail...I don't understand anything! How did they get 1.3 and 0.7? Thanks!</p>

<p>The width of rectangle P is 30% longer than the side of square T. The length of rectangle P is 30% shorter than a side of square T. The area of square T is most closely approximated by how much of the area of rectangle P? </p>

<p>ANSWERS:
F--Approximately 100% </p>

<p>G--- Approximately 110% </p>

<p>H--- Approximately 154% </p>

<p>J--Approximately 205% </p>

<p>K--Approximately 234% </p>

<hr>

<p>Answer: Choice G is correct.</p>

<p>Step 1: Pick a Simple Number to Replace the Variables.
Plug-in for the sides of the square. Make the square have sides of length 10. Since the width of rectangle P is 30% longer than a side of square T, then width = 1.3 x 10 = 13. Since the length of rectangle P is 30% less than a side of square T, then length = 0.7 x 10 = 7. </p>

<p>Step 2: Plug that number into the equations in the question. Now we can solve the areas of both rectangle P and square T.</p>

<p>Square T’s area = (side)2 = 102 = 100
Rectangle P’s area = (length)(width) = (7)(13) = 91.</p>

<p>The area of Square T is what percentage of the area of Rectangle P?</p>

<p>Percent= part/whole=100/91=109.8=110%approximately</p>

<p>Step 3: Plug the Numbers into the Answers Choices. Eliminate Those that Give a Different Result than the Target Number. </p>

<p>The closest answer is G.</p>

2

<p>Um.. since you took the time to type all that out I guess I'll try to answer it.</p>

<p>When you get questions like these, plug in. Since the square is uniform, plug 1 in for the sides. Then follow the question, and get 1.3 and .7 for the sides of the rectangles. As a result, you know the square's area is 1. You know the area of the rectangle is .91 . Therefore the area of the square is approx 110% that of the rectangle. Make sense?</p>

3

<p>If the side of the square is X and the width of the rectangle is 30% greater than that, then the width of the rectangle is 1.3X (130%). Similarly, the length works out to .7X (70%).</p>

<p>Comparing the area of the square (X^2) to the area of the rectangle (.91X^2), gives you approximately 1.1 or 110%.</p>

<p>I don't see the need or advantage of plugging in numbers. The X's cancel out nicely and you have your answer. I guess it comes down to how it is easiest for you to solve problems of this sort.</p>

4

<p>It's more direct/easier to understand with hard numbers (.7, 1.3) as opposed to variables (.7x, 1.3x).</p>

5

<p>What the hell, this is what I did:</p>

<p>Algebra baby</p>

<p>take 's' as the length of the square</p>

<p>therefore area of rectangle =</p>

<p>(s-.3s)(s+.3s) = s^2 - .09s^2 which effectivly means the squares area is s^2 + .09s^2 or the area and about 1/10ths more in relation to the rectangle</p>

<p>Hope you got that</p>

6

<p>haha I'm a lil late but I did exactly what the original post did, and it worked out :-) thought I'd share.</p>