<p>everytime i see a function problem i approach it calmly and try to understand the question.. but i seriously dont understand these types of problems and i miss them 95% of the time. for example this problem..</p>
<p>Let the function F be defined by f(x)=x+1. If 2f(p) = 20, what is the value of f(3p)?</p>
<p>also if any of you have the blue CB book, i could use help on number 8 on pg. 532. (Its a illustrated graph). </p>
<p>Any help would be greatly appreciated</p>
<p>When you have a function defined as f(x)=x+1, that means when you put a random number, n, into the equation, it is replaced with n+1. For example, f(4)=5 and f(-1)=0.</p>
<p>So 2f(p)=20 is the same thing as saying 2(p+1) = 20. You can solve this to get p=9. Now plug this back into the new equation they want you to solve. The problem asks for the answer to f(3<em>p) = f(3</em>9)=f(27). Now we know from before that f(x)=x+1, so f(27) = 27+1 = 28</p>
<p>I hope that makes sense</p>
<p>yeah thanks tanman.. i understand this now. i still feel really skeptical about functions though :/</p>