<p>I am wondering if there is an easy or more efficient way to solve this problem than listing all the combinations? Anyone think this problem is kind of ambiguous? I think the correct answer is (C).</p>
<p>During a magic show, the magician asks a 12-year-old to put all three marbles, two red and one green, into two distinct jars. Given that marbles of the same color are indistinguishable from one another, how many different ways can the 12-year-old put the three marbles into the two jars if each jar should contain a maximum of three marbles and a minimum of one marble?</p>
<p>(A) three
(B) four
(C) six
(D) eight
(E) twelve</p>
<p>The valid combinations are:
1 2
G RG
RG G
GG R
R GG
GGR
GGR</p>
<p>The combinations are 6[C].
Here are a few of new Combinations I’ve Done:
Now taking 3 Reds[R] and 2 Greens<a href=“Indistinguishable”>G</a>:[Please check if correct]
GG RRR
GRG RR
GRRG R
GRRRG
RRR GG
RR GRG
R GRRG
GRRRG
G GRRR
GR GRR
GRR GR
GRRR G</p>
<p>Taking 2 Reds and 2 Greens:
GRRG
R GRG
RR GG
RGR G
RGGR
GRG R
GG RR
G RGR
RG RG</p>
<p>During a magic show, the magician asks a 12-year-old to put all three marbles, two red and one green, into two distinct jars. Given that marbles of the same color are indistinguishable from one another, how many different ways can the 12-year-old put the three marbles into the two jars if each jar should contain a maximum of three marbles and a minimum of one marble?</p>
<p>Three marbles in one jar is not compatible with a minimum of one marble. All three marbles intimates that there only three marbles. </p>
<p>Because it requires a minimum of one marble per jar, then there would be only 4 ways to do it. We cannot put all three marbles in one jar.</p>
<p>You guys think this is a silly and ambiguous question? Is there any other possible ways of interpreting this question leading to more than one correct answer choices?</p>
<p>This question is coming from october 1925 SAT this types of questions require at least 5 minutes of calculation to get the right answers. I never saw this type even in the hardest SAT book.</p>
<p>Haitek, the reason I call it ambiguous is because of the “max three and minimum one” contradiction coupled with the THREE balls. It makes no sense to add “a maximum of three.” </p>
<p>With three balls, this problem is rather silly as the answer could not be easier to determine. How hard is it to write G RG, RG G, GG R, and R GG?</p>