AN EXTREME BEAST OF A MATH PROBLEM 2 (not quite as complicated)

Test Preparation SAT Preparation
1

<p>delete.....</p>

2

<p>Shanice had 56 (b)</p>

3

<p>how'd u do it?</p>

<p>edit, nvm its really easy</p>

4

<p>Use algebra- (I don't know any easier way to do this)</p>

<p>Raphael=3x
Mohammed=x
Shanice= 3x+20</p>

<p>If shanice gave 12 to Raphael
Raphael = 3x+12 and Shanice=3x+8</p>

<p>And Raphael gave 1/4 to Mohammed
Raphael= 2.25x+9 and Mohammed = 1.75x+3</p>

<p>And then Raphael had 12 more candies than Mohammed
2.25x+9-(1.75x+3)=12
.5x+6=12
.5x=6
x=12 (Mohammed's candy amount before)</p>

<p>And from earlier Shanice=3x+20
12(3)+20= 36+20=56</p>

<p>Bubble in B and you are finished.</p>

<p>Hope this helps.</p>