<p>heres another problem from my AP Physics review sheet, can someone help?
An object is thrown straight up into the air and reaches its highest point 3 seconds later.
Assuming the gravity of earth has an acceleration of 9.8 m/s2 downward, What was the objects average velocity during the last second of its downward trip(cought at the same height)?</p>
<p>1.) Plot object’s path as a parabola with time on the x-axis and height on the y-axis.</p>
<p>t=-9.8(x-3)^2</p>
<p>2.) If it reached its highest point after 3 seconds, it will come back down in another 3 seconds. So the last second of its downward trip will be between t=5 and t=6. Find out what the difference in height between those two times was (using the equation) and divide by 1 sec. (so you get velocity). That’s average velocity.</p>