Anybody figure out which math section was experimental?

<p>I had 4 math sections and the first one was way harder than the 3 that came after it. It was the one with the freaking function at the end. What was the answer to that btw?</p>

<p>the one with the two circles combined together that made like a breast shape :smiley: that was the hardest section imo- was that experimental?</p>

<p>I believe i had eng experimental.
As for the function at the end problem, the answer is f(x)^2</p>

<p>I had two writing sections that had 35 question each. I wasn’t used to this in my practice tests so I’m pretty sure one of them was the experimental? And I had them back to back which really sucked…(:</p>

<p>sorry bro but the math question with two breast is not experimental. I remember that problem and it was 96 pi + 64. My experimental was critical reading which I really suck at D:<.</p>

<p>10 char./…</p>

<p>I don’t think the functional notation problems are experimental. I think they’ve been tested before and are new to the test this year.</p>

<p>I got math as experimental.</p>

<p>guys, i had 3 CR… I can’t figure out my experimental!! please help. I’m confused. I don’t remember but I believe I had 4 math and one was TERRIBLE and the other ones I did full so I am soooo nervous which one is the experimental one :frowning: I remember leaving 2 pages EMPTY in one math section! the last pages seemed impossible and I had like 3 minutes to do 2 pages so I couldn’t. Is that the experimental one?</p>

<p>@ cchen64 the two cirlce one was 96 pi + 64? not just 96 pi? </p>

<p>EFFFFFFFFFF LIFE.</p>

<p>And I can’t really remember but I think I got CR as experimental because I had two sections in a row at one point and the questions on one of them seemed a bit unconventional for the SAT…the section wasn’t exactly very difficult; it just seemed kind of odd.</p>

<p>^ :frowning: I put 96 pi too…are we sure it’s 96pi + 64?</p>

<p>I was pretty sure it was just 96 pi…since the arc length was 270 degrees, that’s 3/4 of a circle, so 3/4 of the circle’s area (r=8, so 48 pi) times 2 since there were 2 of them…which equals 96 pi right?</p>

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<p>That was my reasoning also. Seems right to me.</p>

<p>I feel like I’m missing something though…it seemed too easy when I solved it, especially seeing as it was the last problem in the section…):</p>

<p>cchen is right. I also had 4 critical reading sections so that math section counted. As for the answer to that problem with the two circle arcs the answer is 96pi+64. I will explain why. The logic is that you had to draw a square at the center of the two circles to actually make them two 270 degree arcs. So the two arcs would be 96pi but then you have to add the square which is 64.</p>

<p>“I was pretty sure it was just 96 pi…since the arc length was 270 degrees, that’s 3/4 of a circle, so 3/4 of the circle’s area (r=8, so 48 pi) times 2 since there were 2 of them…which equals 96 pi right?”</p>

<p>if you use this, you’re neglecting the squre w/ sides eight in the middle. i wish i could draw a picture…but if you draw 3/4 of both circles, you’ll see a box in the middle w/ sides 8 so you need to add 64. hope this helpsss</p>