<p>hard formulas or equations to remember? you can put all this stuff into the text editor or w/e</p>
<p>-avg value formula (dont get mixed up w/ avg rate of change)
-before I forget, the calc tools progra, free from ti website (ti-89)
-trig integrals
-mean value theorem
-rolle's theorem</p>
<p>anything else especially tricky or hard to remember?</p>
<p>Hmm, well I’m sure there are good study sheets with formulas out there, but the things I would suggest are:
-Intermediate Value Theorem
-Trapezoidal Rule/Simpson’s Rule
-Quotient Rule
Could someone explain to me when you use the average value formula and when you use the avg rate of change?</p>
<p>Definitely memorize the differential equations and their solutions. That will save a lot of time.</p>
<p>^ only on the multiple choice, right?
Don’t you have to show your work (separation, integration) if its on an FRQ?</p>
<p>From what I remember, yes. But, you still have to start with the right differential (although they may give you the differential, I’m not sure), and you should be able to recognize your solution. You have to show your work, but this is a good way to check it.</p>
<p>what’s the difference again btwn average value and average rate of change?? im getting confused now…</p>
<p>I think average value is the average y coordinate or something similar. Because don’t you divide the area by the change in x? </p>
<p>Average rate of change is, I think, finding the difference in the initial and final y coordinates and dividing that by the change in x. </p>
<p>I’m recalling this from a year back, so take my answers with a grain of salt.</p>
<p>Okay I got it. You use the avg rate of change if they ask you to approximate something and they have already given you a table. It’s like the slope. The avg value on the other hand is finding the total area and dividing it by (b-a) or whatever.
^Senior0991 is correct.</p>
<p>If people would think of average rate of change = average value of the rate of change, people would do better.</p>
<p>i.e. average rate of change of f(x) = 1/(b-a) * integral(f '(x), x, a, b) = 1/(b-a) * (f(b) - f(a)) = [f(b) - f(a)] / (b - a).</p>