AP Calc Question (1996 test #6)

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1

<p>line L tangent to graph of y = x - (x^2)/500 at the pt Q</p>

<p>a) find x-coordinate of Q</p>

<p>b) write eqn for line L</p>

<p>I would appreciate any help you could offer me thanks</p>

2

<p>There isnt enough information to answer that question. Was there any more to the question. Are you finding a line through the origin and tangent to the graph?</p>

3

<p>Yeah you need coordinates to where the line should be tangent to.</p>

4

<p>You can find it in terms of Q, but I don't think they would ask that...so yeah, some information is missing.</p>

5

<p>yeah i have the exact same quesiton... i have the website to help someone answer within the next hour... please</p>

<p><a href="http://www.marymount.k12.ny.us/marynet/StudentResources/math/FellowshipProject/96Q6.pdf#search='Line%20l%20is%20tangent%20to%20th%20e%20graph"&gt;www.marymount.k12.ny.us/marynet/StudentResources/math/FellowshipProject/96Q6.pdf#search='Line%20l%20is%20tangent%20to%20th%20e%20graph&lt;/a&gt;'&lt;/p>

6

<p>That makes a lot more sense
y-y1= m(x - x1) and x1,y1 = (0,20) and m = derivative evaluated at x and y = the function
sp
y - 20 = (1-2x/500)*(X-0)
and then you plug in what is y and you get
x^2/500=20
x^2 = 10000
X=100
Then you can do the rest of the problem , I have to go back to physics.</p>

7

<p>here you go
<a href="http://www.ahs.albany.k12.ny.us/AHS/class/calc/96ab/question6.html%5B/url%5D"&gt;http://www.ahs.albany.k12.ny.us/AHS/class/calc/96ab/question6.html&lt;/a&gt;&lt;/p>