<p>If the function is increasing and you use the right Riemann sum it is an overestimate and the opposite for the left Riemann sum for an increasing function. And then left is an over and right is an under for a decreasing function.</p>
<p>What about something like #5 in 2011?</p>
<p>I have a question, for the FRQ’s, is showing the work that leads to my answer sufficient enough to “explain my reasoning” or must I directly explain it in words/some symbols to prove it?</p>
<p>Just wanted to share. I thought these review guides were really helpful:
<a href=“http://www.northcanton.sparcc.org/~hck/data/jjk1nc/files/APperc20Calcperc20Reviewperc20Answerperc20Key_JRahn.pdf[/url]”>http://www.northcanton.sparcc.org/~hck/data/jjk1nc/files/APperc20Calcperc20Reviewperc20Answerperc20Key_JRahn.pdf</a>
<a href=“http://www.luoyong.org/wp-content/uploads/2012/05/AP微积分AB公式大全（2012版）.pdf[/url]”>http://www.luoyong.org/wp-content/uploads/2012/05/AP微积分AB公式大全（2012版）.pdf</a></p>
<p>What are you guys most worried about? I always get tripped up by the Intermediate Value and Mean Value Theorems. I also need to completely review modeling and optimization. </p>
<p>I feel like in all the practice I’ve done on previously released FRQs, no matter what, in those 6 questions they find some way to ask you about nearly everything you’ve learned.</p>
<p>Soo scared for tomorrow!</p>
<p>No need to be worried, calc is one of the easier APs</p>
<p>I’m worrying because I reaally struggle with the FRQ’s.</p>
<p>How can you know which is the top function without a graph?</p>
<p>Are the arc lengths testable? (s = Integral from a to b (sqrt(1 + (dy/dx)^2))</p>
<p>Gha. Who’s ready for tomorrow. Meeee.</p>
<p>The exam is tomorrow; this feels so surreal.</p>
<p>What is the period of Abs(sin x), where abs = absolute value…??</p>
<p>Any good calculator tips / tricks to use?</p>
<p>Do you know how to take the derivative with your calculator?</p>
<p>^^^ Pi I think, although that is not really something you need to be studying</p>
<p>Somebody please help?! </p>
<p>A particle moves along the x-axis so that its velocity at any time t is equal to greater than 0 is given by v(t) = 5te^(-t) -1. At t=0, the particle is at position x=1. What is the total distance traveled by the particle from t=0 to t=4?</p>
<p>@collegedreams29</p>
<p>Is that a calculator problem? Either way:</p>
<p>Total Distance Traveled = The integral from 0 to 4 of abs(v(t))dt</p>
<p>I dont know to do fancy stuff on here, but thats how you would set it up. I think you may need a calculator to solve it though.</p>
<p>Take the antiderivative from [0,4] for v(t) because this will give you the total distance travelled by the particle (area under the curve). You should get [integral</a> of 5te^(-t) -1 on interval 0 to 4 - Wolfram|Alpha](<a href=“integral of 5te^(-t) -1 on interval 0 to 4]integral - Wolfram|Alpha”>integral of 5te^(-t) -1 on interval 0 to 4 - Wolfram|Alpha)</p>
<p>Then, you have to add 1 to this answer because it is the initial condition (0,1). You have to add one because you must add onto the distance the integral didn’t cover. I think you should get 1.5ish.</p>
<p>I hope that helped. I am not good at explaining math over the Internet, but something is better than nothing. We are all on the same boat.</p>
<p>I’m trying to do it on my calc but it just won’t do it 
It keeps giving me an error. Anyone using a Ti-89 tomorrow? It’s a calculator MC</p>
<p>@rishbu, we don’t need to do the absolute value of v(t) here? when do we know we have to?</p>