for 2c i know i got a negative value. Not sure what I got, Ill do it out right now and see.
I got -3.812 for 2c.
@kayjay88 you’re right, I remember it being negative but a large number, which was really weird
its d/dx((1+x+e^(x^2-2x)-(X^4-6.5X^2+2)) @x=1.8 which is -3.812
guys lets create a comprehensive answer sheet
@kayjay88 then I must have done some stupid mistake in the calculation because, thats exactly the way I did it and got a different number.
@zach1198 for 2c did you calculate it using h’(x)=f’(x)-g’(x) at x=1.8?
Yes, except i just took math 8 of f(x)-g(x).
1a) integral of R(t)= 20sin(x^2/35) from 0 to 8 = 76.570
1b) derivative of R(t)-D(t)=20sin(x^2/35)-(-0.04t^3+0.4t^2+0.96t)=1.036, its increasing because d/dx is positive.
For 5c, -2, 1, 4?
Wait no -1,1,3
yup thats what i got
anyone got 8 for 6c? im 100 percent on that one.
@zach1198 okay cool I just wanted to make sure that was right
@hark123 can you please show your math? I got 1/32.
@kajay88 R(t) and D(t) are already rates, so you don’t take the derivative of R(t) - D(t) to find the rate of change of the water. The rate of change of the water at t = 3 would be R(3) - D(3) = -0.314, so it’s decreasing.
@zach1198 it’s 8, you can work it out yourself to see, find slope first and then find the second derivative but no need to simplify just evaluate at (-1,1)
@hark123 if you take the derivative of dy/dx and then plug in you get 1/32.
d^2y/dx^2 = ((dy/dx)(3y^2-x)-(y)(6ydy/dx-1))/((3y^2-x)^2) plugin and you get (¼)(4)-(1)(½)/(4)^2 =1/32
I even redid the problem again and got 1/32. If you wouldn’t mind showing how you got 8, so we can see where one of us went wrong. Thanks.
1a) integral of R(t)= 20sin(x^2/35) from 0 to 8 = 76.570 gallons
1b) R(t)-D(t)=20sin(x^2/35)-(-0.04t^3+0.4t^2+0.96t) at t=3 =-0.314, its increasing because d/dx is positive.
1c) its where R(t)-D(t)=0 which is at t=3.272
1d)30+76.570+ integral 8 to w R(t)-D(t)=50 --> 106.570+integral 8 to w R(t)-D(t)=50
@dogeater you are right thats what i got on the ap just screwed up while writing the answer
Yes you’re correct, apparently, I did (1/2)/16 and I flipped it and did 16/2 and it was 8. My mistake…
For 1b) wouldn’t it be decreasing