<p>Oh.. anyway, I wrote the inverse wrong. It should read 1/g'(x) not 1/ inverse g'(x)</p>
<p>Yay i actually got some right..didn't do too hot on 3, 4, and 6 though</p>
<p>On 3d, in general, the formula for the derivative of g-inverse of x is that it is equal to 1/g'(x).</p>
<p>If you've never derived this formula before, you can do so from the equation y = g(x).</p>
<p>The inverse of this is x = g(y). Implicit differentiation yields that 1 = g'(y)*y', and that y' is therefore equal to 1/g'(y).</p>
<p>The equation of a tangent line in general is y - h(a) = h '(a)[x - a], where in this case h(a) = g-inverse of a, and a = 2. So h(2) = g-inverse(2) = 1 and h'(a) = 1/g'(1) [since it's g'(y), not g'(x)] = 1/5.</p>
<p>Therefore, the equation of the tangent line is y - 1 = 1/5(x - 2)</p>
<p>Oh my goodness, I think I did put 1/1</p>
<p>Shoot! I JUST DID THIS ONE TOO!!!!!! AHHHHHHHHHH</p>
<p>I totally get it, I just didn't get it the time I was testing!!</p>
<p>thanks math prof
has nebody seen form b yet?
its SOOO MUCH EASIER THAN THE ONE WE GOT!
seriously unfair</p>
<p>Well not the same problem but one like it</p>
<p>Thanks mathprof...you should be my Calc 2 teacher, or maybe Calc 1, if I failed this test!!</p>
<p>Form B is for everyone outside of the Continental U.S.</p>
<p>There's another form for those who make it up.</p>
<p>I've noticed Form B has always been harder than Form A - until this year</p>
<p>On three I just wrote the intermediate value theorem proves part a and mean value on part b...I probably should have actually done the math on b, but I was burnt out</p>
<p>I can't be your calc teacher unless you happen to move into my high school and retake AP Calculus AB. =)</p>
<p>Crap man...I have got an A in calc, but I'm struggling to get a decent F on this exam. That's depressing.</p>
<p>29% for a three that's what I repeat to myself...29%</p>
<p>The curve can't be better than 65% for a 5 can it?. I hope it is but it seems to good to be true if it is. It seems like some people actually did good, unlike me.</p>
<p>i hope the curve is 60% for a 5
damn i wish we could find out about m/c cuz it basically dictates what i got since FRQ is stupid
dumb collegeboard for being lazy and reusing m/c questions</p>
<p>In 2003, it was 66/108 for a 5, which is just a smidge over 61%.</p>
<p>Could it be lower? I suppose so... but I can't imagine they'll go too much lower.</p>
<p>^^ yeah i guess
cb better give pity points for frq
im still seething over the fact that form b is so much easier</p>
<p>I have a few questions, hopefully someone can answer em for me ^^ regarding the free response, I will basically post the parts I wasn't sure on, and can ya tell me whether I got it right or not? It would be very much appreciated ^_^</p>
<p>1c) pi/2 * integral of ((20/(1+x^2) -2)/2)^2) between -3 and 3. Answer I got was 174.2685.</p>
<p>2c) t = 3 is when the absolute maximum occurs because the net rate changes from positive to negative at that point. Then I did integral of f(t) between 0 and 3 and found F(3) to be 5876.5908 gallons. then integrated g(t) between 0 and 3 and got 750. 5876.5908 - 750 = ~5127 gallons</p>
<p>3a and 3b) Do I get full credit for just saying for a that the intermediate value theorem guarantees it? and for b that mean value theorem guarantees it? Does that get full credit?</p>
<p>5d) I put that it was under approximating because r"(t) < 0. (I have a feeling i'm wrong)</p>
<p>same question as mael - </p>
<p>do we get credit for just identifying the theorem necessary, or do we have to prove the theorem (and/or define it) in order to get full credit?</p>
<p>they would want you to show why the theorem would work in the particular case for the Intermediate, you had the two end points and to say it's continuous and diferentiable so the theorem works.</p>
<p>And for MVT, same thing, show the slope at c and the average slope.</p>
<p>You would get marks I think for just identifying the theorem but from what my teacher said they would want mathematical proof and showing that you understand the conditions for each theorem.</p>
<p>1c. Agree, with the answer as written, but I'm pretty sure that the 5 in the fourth decimal place is an error. Luckily, it shouldn't be scored.</p>
<p>2c. Probably insufficient. In order to justify an absolute maximum, you also have to check the endpoints.</p>
<p>(EDIT: Not sure how many points this one is worth, but I'm projecting four, and that not checking the endpoints would lose one of the four points.)</p>
<p>3a and 3b. I'm not as sure on this one, but my guess is that you have to establish the hypothesis of the theorems before quoting them. In other words, before quoting the Intermediate Value Theorem on 3a, you would need to probably establish the values of h(1) and h(3) to ensure that -5 was actually between them. Similarly, in order to use the Mean Value Theorem on 3b, my guess is that you would need to establish that the average rate of change is actually -5. (EDIT: You wouldn't have to establish the "slope" at c, because the slope of c is unknown when only provided with a table of values, though.)</p>
<p>When referencing these theorems, you don't need to necessarily refer to them by name, as you can also basically describe what they do instead (EDIT: but you have to be pretty specific), but naming the theorems once you've established the hypotheses is also sufficient.</p>
<p>(EDIT: Scoringwise, I'm guessing those are each 2 point questions, and that you would probably earn the 2nd point of both questions.)</p>
<p>5d. Seems good to me. I'm thinking that they will say that r' is decreasing in the rubric, but r"<0 is equivalent.</p>