<p>Determine this derivative... should be simple, but I can't figure it out:
d3/dx3 [f(x) g(x)] </p>
<p>a.k.a. [f(x) g(x)]'''</p>
<p>Product rule to find the first derivative</p>
<p>First x Derivative of the second + Second x Derivative of the first</p>
<p>Theeeeeeen...go from there...heh</p>
<p>Here's my shot at it:
y'= f'(g(x))g'(x)
y''= f''(g(x))2g'(x) + f'(g(x))g''(x)
y'''= f'''(g(x))3g'(x) + f''(g(x))2g''(x) + f''(g(x))g'(x) + f(g(x))g'''(x)
I don't know if it's correct but I that's what my answer would be.</p>
<p>Thanks guys. I actually figured it out a little bit after I posted. I forgot you can expand it sort of like you would (x+y)^3.</p>