<p>yes covalent network is much stronger than ionic bonding and some of the examples are C as a diamond and Sio2 which is Quartz.
OK here comes a question</p>
<p>The types of hybridization by carbon atoms we can see in propyne molecule, CH3CCH, include
1. sp
2. sp2
3. sp3</p>
<p>hey guys! come up with the answers!</p>
<p>sp and sp3</p>
<p>Which description applies to the reaction below?</p>
<p>AlCl<em>3 + Cl^- ---> AlCl</em>4</p>
<p>A. amphotorism
B. anion hydrolysis
C. Arrhenius neutralization
D. Lewis acid-base reaction
E. Bronsted-Lowery proton transfer</p>
<p>another question, what do you get to use on the MC part, the periodic table? equations chart? anything?</p>
<p>You get a periodic table. Can anyone explain the propyne question?</p>
<p>I think you get only the periodic table. No calculator, no equation chart.</p>
<p>I don't know the answer to your MC question, though</p>
<p>Doctorcroc, here's how it goes
if you draw CH3CCH, it becomes like this
H
H-C-C-C-H
H</p>
<p>so the first C is sp3 (see four atoms around the first C?)
and the second and third ones are linear since it's just C-C-C-H(linear)</p>
<p>the answer is D</p>
<p>can anyone confirm the use of the periodic table?</p>
<p>yeah...and i dont get the propyne question either...</p>
<p>oops, my CH3CCH is ruined.... i see the difference btw what i write and what it shows;; ok so the H in the first row has to be on the first C, not on the H
and same for the H in the third row..</p>
<p>Ah I see, so one C is bonded to 3 hydrogens and 1 carbon whereas the others are just bonded to two other atoms. Thank you.</p>
<p>To clarify, when you draw a hydrocarbon, you start out with carbons and then attach the hydrogens and oxygens right?</p>
<p>ummm i dont think there are oxygens in Hydro(H)carbons(C)</p>
<p>methane.... CH<em>4
ethane.... C</em>2H<em>6
propane...C</em>3H_8
etc...</p>
<p>Doctorcroc, yes you're right except that there are NO oxygens in the basic hydro carbons like what Vhoidz said :-)</p>
<p>another question!
Actually i am working on this question now..</p>
<p>The standard enthalpy of formation of HI(g) is 26kJmol^-1. Which of the following is the approximate mass of HI(g) that must decompose into H2(g) and I2(s) to release 500.kJ of energy?
a. 250g
b. 650g
c. 1300g
d. 2500g
e. 13000g</p>
<p>everyone,, ,Animo!</p>
<p>Diana oh</p>
<p>if you figure out this problem
coould you show us, im not sure how its done...</p>
<p>Does this require a born-haber diagram?</p>
<p>oooh.. this is really tough!
i solved this way: since 2HI->H2+I2, the enthalpy change here is -26kJ. 500/26 = 19.2308 meaning that the actual reaction took 19.2308moles of HI to be decomposed into H2 and I2. So in order to get the mass of HI, 19.23*(1+127)=2461.44 which is approximately 2500g. The answer is d but im not sure about the solution......... any help?</p>
<p>yeah i think so</p>
<p>if anyone is interested in starting a chatroom for tonight or something let me know (pm , or AIM me)</p>
<p>does anyone know how much solids are on the test....like properties of solids...?
VSEPR?</p>
<p>oh here in S Korea it's already 3 am.............;-( VSEPR always appear on the test,, but the number of questions varies. but i think it frequently appears in the FRQs so you've gotta be familiar with it :D</p>
<p>which ever one has double bonds or the strongest intermolecular forces</p>
<p>im not sure what you are asking....</p>
<p>new question:</p>
<p>how do you know if a reaction is happening spontaneously?</p>
<p>Negative delta G (free energy).</p>
<p>Write the following reaction:</p>
<p>Ammonia solution is added to a silver chloride precipitate.</p>