ap physics b circuits problem

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1

<p>Alright, circuits test tomorrow and i can't figure out this god damn problem. I will try and draw the circuit as best i can on here....so we have a 4 ohm resistor. That resistor is in series with this next big thing im going to describe. a 2 ohm and a 1 ohm resistor are in series. The 2 and 1 ohm resistors are in parallel with a 5 ohm and 1 ohm resistor in series. The voltage is 12. What is the power dissipated by the 5 ohm resistor.</p>

<pre><code> -----2ohm---1ohm--
</code></pre>

<p>4ohm———l l
-----5ohm---1ohm--
Help!!</p>

2

<p>crap that didnt come out right…</p>

3

<p>Would it be possible for you to put a picture up of the problem because I am a little confused?</p>

<p>Without the picture I’ll tell you what my general strategy would be, I would find the equivalent resistance using appropriate formulae, and then I would find the amplitude using
V = IR, the R being the equivalent resistance for all those resistors, once I found the amplitude I would use Power = (I^2)*R, that R being the specific 5 ohm resistor.</p>

4

<p>Sorry, didn’t mean amplitude I meant amperage</p>