<p>i agree. post em please!</p>
<p>hmmm.....Perhaps this isn't relevent to this discussion but...Suppose that I got a perfect score on the mechanics multiple choice and 25/45 on the mechanics free response...Given that the mechanics test was fairly easy, what score do you think I'll get?</p>
<p>aaaagh...I screwed up...</p>
<p>Definitely a 5 if you actually did perfectly on the MC.</p>
<p>is there a link anywhere to the mech answers like mr. calculus or anything?</p>
<p>hey i forgot exactly the q. but umm question 3 on E and M. which way was teh induced current flowing. clock wise or ccw?</p>
<p>err someone want to post the answers to the whole last E and M question?</p>
<p>anyone at all???</p>
<p>come on a lot of people are viewing.... then again im not posting either. so ill take that as a no one is very sure</p>
<p>we'll see in july i guesss</p>
<p>I'm pretty sure my answers are right for EM3</p>
<p>a) Counterclockwise, because induced B field is out of the page, RHR.</p>
<p>b) I=(BLv)/(L<em>lambda+2vt</em>lambda)</p>
<p>c) F=(B^2<em>L^2</em>v)/(L<em>lambda+2vt</em>lambda)</p>
<p>d) graph looks like 1/x, with y-intercept of (B^2<em>L^2</em>v)/(L*lambda)</p>
<p>e) Decreases, because force is to the left by RHR.</p>
<p>sorry darcy but i think our teacher told us the graph was a straight line...</p>
<p>anyone else? or rebuttal from darcy?... lol</p>
<p>oksannadog613: Your teacher is wrong, then. Look at the F equation. It's not a linear relationship.</p>
<p>i mean -------- not diagonal. bc the velocity is constant or sommat</p>
<p>err force ......................</p>
<p>really weird tho i had put it ur way. and was told it was wrong. i wasn't sure bout it when i put the 1/x down......... i was really bummed when he told us it was ------ like that . i was hoping the last part was still decreasing</p>
<p>I agree with Darcy's answers...I'm pretty sure they are all correct.</p>
<p>It means I screwed up Parts A, B, and C tho and I didn't label the intercept for D. Wow...this is looking bleak.</p>
<p>Anyone have answers to #1 and #2 for E/M??? Or Mech?</p>
<p>Does anyone have answers to Mech #2??? Here are my answers:</p>
<p>(a) r = 3.83 * 10^6 m
(b) mass = 6.63 * 10^23 kg
(c) E = - 5.37 * 10^9 J
(d) Period would be less than given period because T is proportional to r by Kepler's Law of Periods.</p>
<p>(e) I got this wrong because I went back and changed it. I thought Conservation of Angular Momentum did not apply because the gravitational attraction changes as the satellite orbits and therefore experiences a torque which would produce change in angular momentum. It may be a Cons. of Ang. Momentum problem though. Anyone else??</p>
<p>Let me know if you agree or disagree or want further explanation.</p>
<p>i used conservation of angular momentum....but im pretty sure it was wrong...i just had extra time, and wanted to put somrthing down..</p>
<p>I rechecked the problems. For Mech #2, it says that the GS is some distance from the SURFACE of mars, so i forgot to add the radius of Mars into my mrv = mrv calculation for angular momentum. In addition, it says that the GS is 10^5 m from the surface, but the radius of mars is about 10^6 meters...
Hopefully the answer is just 1 point of out that.</p>