Yes
@Newdle O well i think those are the only official MC by the college board. Everything else you can practice is going to be third party (Princeton review, learnerator)
@sscharter I can definitively say that having a formula sheet/calculator on the Multiple Choice will not change anything. If you have to play Where’s Waldo on the Formula sheet on the day of the test, then you’re hosed. I’ve never once used the formula sheet.
Also, no problem on the MC is ever challenging because of the arithmetic involved. Never did I get a (practice) question wrong on a released exam because of having to do pen-and-paper calculations, it was always due to conceptual errors. The problems will mostly be conceptual.
ok, thank you! that boosted my confidence… I was just so scared they would change all the question types like my teacher said.
Could someone please explain mcq no.15 of the 1993 paper?
So, the total energy a system can have is u+k, the potential energy and the kinetic energy. Since at X1 the u = -2 j and the k = 1 j, the total energy is -1 j at all points. This means that the two points at which u = -1 j are the farthest the particle can move. So, the particle can not get to either x0 or x2.
Thanks !
Could you please explain 19 and 34 of the 2004 paper ?
Eek! The exam is on Monday. May Newton be with us.
Do you guys think that the new curve will be the same 50/90 thing or worse, 70/90 or even 80/90? I think I can reliably get a 75% or so on the Mech exam. In better scenarios, probably the high 80s or low 90s. Thanks!
Yup, sure…
19 - the equation for theta = theta max (sin (omega * t)) where omega = 2pif, so since the frequency is 1/t = 1/2, if you plug all the stuff in you should get choice B which is the correct answer!
34 - since the stone is stuck on the tire, it is under the influence of circular motion. in circular motion, the force and the acceleration due to the centripetal force are both directed inwards. Therefore, when the stone is first picked up, it will be at the bottom of the wheel, and the acceleration is upwards - choice A
^ bump!!! How many mc and free response points do you think we need? I really hope they don’t change the curve that much 
If you can get 28+ (out of 35) on the MC and 30+ (out of 45) on the FR on any given practice test, you are a lock for a five. Even if the curve is a little harsher than normal, even if your performance on the actual exam is a bit worse due to sampling variation.
For graphing questions, is it acceptable to run a regression analysis on the graphing calculator instead of doing the rise over run formula? I ask as I know they have ranges of acceptable answers and running a regression analysis seems to be a way to guarantee that you’ll be in their range (on practice FR’s, sometimes I’ve been slightly over or slightly under their acceptable range when just doing it by hand).
If I can get around 23/35 MC right how many free resp points do I need out of 45 to get a 4?
@stoopidfoose … Not many at all. It’ll change from year to year, but honestly if you get a 23/25 on MC you know enough physics to do fine on the FRQs and get a 5.
@Mathinduction No. You must explicitly show two points that were taken from your best fit line (that are not data points) used in calculating slope. Also, LSRLs are “perfect” in the sense that they will superimpose the true best fit line for your data, regardless of whether it makes sense. For example, not always will your Regression line go through (0,0), when it should.
2014 Exam:
http://mralsterscience.■■■■■■■■■■/uploads/3/8/0/0/3800138/ap_physicsc_m_practice_exam_2014.pdf
Can someone help me with part C of Mech 3 FRQ on this:
http://mralsterscience.■■■■■■■■■■/uploads/3/8/0/0/3800138/ap_physicsc_m_practice_exam_2014.pdf
I don’t understand where the sin(theta) came from
Can someone help me with part B, number 1, of the Mech 3 FRQ in the 2012 released AP physics C exam?
(if link doesn’t work its on collegeboard)
I understand that angular acceleration equals acceleration over radius which is what i did to directly get the answer but why is applying newton’s 2nd law of rotation necessary at all? After-all, I get the same answer anyhow.
@theboss262 uh there are 35 MC… is that what you meant to say
Can someone explain to me #20, 22, 29 on the multiple choice for Mech 2014?