AP Physics Problem ...Can you solve it?!

<p>A pendulum with a mass of 2 kg and a length of 3 meters is pulled back 13.75 degrees from the vertical. What is it's Potential Energy ? It is released from its original position. What is its tangential velocity when it reaches the bottom of its swing? What is the pendulum's tangential velocity, the tangential acceration, kinetic energy, potential energy and tension in the suspension rod when it reaches its starting position after one swing?</p>

<p>assuming no loss of energy due to friction
assuming the potential energy at the bottom of the swing is 0J,
PE at start = mgy = 2<em>9.8</em>(3-3cos13.57)</p>

<p>at bottom of swing,
v=sqrt[R<em>centripedal accelaration]=sqrt[R</em>g]=[3*9.8]
-note at bottom, the centripedal accelaration = g</p>

<p>with 0 friction loss, back at its starting position,
a=9.8<em>sin13.75
KE=0J
PE=2</em>9.8<em>(3-3cos13.57)
T=m</em>centripedal accelaration+wcos(angle)=0+2<em>9.8</em>cos13.57</p>