<p>This problem seems simple enough...but my answer is a lil off! There is a 6kg block at the top of an incline plane. The block is 30 meters high and the angle between the plane and the ground is 37 degrees. The question is what is the velocity of the block once it reaches the bottom of the plane? And oh yeah no friction. I keep getting 27.95, and the books says 24.249! What is goin wrong?</p>
<p>Fnet = m(a-gsinx) would be the force to hold it up there so when let go</p>
<p>ma = mgsinx
a = gsinx
a = 9.8sin37 = 5.898 m/s^2</p>
<p>distance travelled = hypotenuse of right triangle: sin 37 = 30/hypotenuse ---> distance = 49.85 m</p>
<p>vfinal^2 = vinitial^2 - 2ad
vfinal^2 = 0 - 2(5.898)(49.85)
vfinal = 24.249 m/s</p>
<p>You can use Eg = Ek</p>
<p>mgh = 1/2(mv^2)</p>
<p>gh = (1/2)(v^2)</p>
<p>(9.8)(30) = (1/2)(v^2)</p>
<p>v = 24.249 m/s</p>
<p>Sorry, you should probably use AblestMom's method.</p>
<p>Eg=Ek is the way to go any time you have an object that's going to be moving downwards neglecting friction, for sure.</p>
<p>What does Eg and EK stand for?</p>
<p>Potential and Kinetic energy?</p>