HEY UNIFORM CIRCULAR MOTION QUESTION please help… So for uniform circular motion, as mass goes up does the period get larger or smaller?? This has to with the problem where you;re spinning a rubber stopper on a string at a constant velocity and constant radius. Any help would be appreciated. Thank you (:
@wanderlustgal Using orbits as an example, v=Gm1m2/r^2. Substituting v for 2pirf, you find that the period gets smaller if mass is larger with a constant velocity and radius. You have a higher frequency which corresponds to a smaller period since T=1/f. Another example, F=ma=mv^2/r. Intuitively if the mass is larger and results in the same velocity as the smaller mass, with radius being constant, the force applied will be greater.
Hint: See relation between Fnet, m, and T.
http://www.physicsclassroom.com/class/circles/Lesson-1/Mathematics-of-Circular-Motion
@leaguemaster420 Bless your soul. Thank you so so much. I hope you get that 2400 or 36 or get into that college or whatever it is you’re on this site for. Thanks!
Hey guys another quick question; we have to explain why delta u can be negative or positive… i dont understand this at all anyonee???
@wanderlustgal Thanks. I actually have a 33 ACT lol. I actually think AP physics is fairly easy; AP calculus is a different story… Anyway, the simple explanation is kinetic energy is always positive or zero. The equation is delta U=0.5mv^2. Since v is squared the value can never be negative.
@wanderlustgal Sorry for misreading your question. Delta u is potential energy, my bad. When kinetic energy is zero, potential energy is “stored in the object” and eventually converted to kinetic energy hence being positive. If the object is below your frame of reference due to the equation being U=mgh, there would be a negative value for potential energy. Hope that helps.