<p>Yay! Lol I’m sleep deprived so sorry 
I have like a thousand and one exams this week!</p>
<p>For the part of number 6, you should have taken you formula in terms of k from part c and set it equal to the points found in you confidence interval in part a. This would give about .03-.05. I don’t remember exactly.</p>
<p>Anyone remember original confidence interval?</p>
<p>It was 9600 students with a 28% proportion, don’t remember what % CI though (99 I think?)</p>
<p>But yea this was pretty easy compared to how much I was freaking out about it.</p>
<p>Was 2(c) the probability one…?</p>
<p>Overall I was expecting much much worse and am very pleased on how nice College Board was to all of us today. :)</p>
<p>The multiple choice I know I got at least 33 or 34 correct and on 4 or 5 of them I narrowed it down to 2.</p>
<p>The free response questions #1 - #3 and #5 were easy. #6 wasn’t too challenging, but I think by then I was worn out. I honestly don’t remember #4, but I remember filling in or at least BSing all of it.</p>
<p>^I think #4 was a hypothesis test? I can’t quite remember either. Same w/ me on the MC; I thought a few of the later questions (in the 30s) were pretty challenging.</p>
<p>For FRQ1a, was it not Normal? For part b, do you interpret it like “the player is ___ standard deviations above the mean?” and for part c, did you find the z scores of both speed and strength for each player, find the probability of them both, then multiply them together?</p>
<p>For FRQ2b, I said they were not independent because I did test for independence: P(AandB)=P(A)P(B), P(A|B)=P(A), and P(B|A)=P(B). Is that right?</p>
<p>confidence interval on 6 (a) was like .268ish to .291, if I remember correctly. And for the last part of 6 you set .25k+ .25 equal to both of those and solve for k to get the interval.</p>
<p>that’s exactly what i did. at first i did what most people did and set .25 + .25k equal to .28, but it said use the confidence interval from part (a)…</p>
<p>You didn’t actually have to solve for k; you could’ve just used the two endpoints from your initial interval and transformed them with your equation from (c).</p>