<p>how did u find that answer for the one that asked to find the median of the probability distribution</p>
<p>Since cumulative probability at 1 was 0.55, I just did a proportion to find where the median was (1/0.55=x/.5). Not sure if that's right, but the answer seems right.</p>
<p>yep. that's what i had</p>
<p>um... a median is a specific value is it not? i just said it was 1... if you had a stemplot with 55 dots above it, it would still make the median 1* keep in mind you will very rarely get a median not part of the data set</p>
<p>The possible values are all discrete integers, so how could the median be a non-integer? </p>
<p>My answer was 1 because it was greater than the cumulative proportion for 0 (.35) and less than the cumulative proportion of 1 (.55) which means .2 of the values were 1. And one of those values of 1 occurred when P(X<x)=.5 (the cumulative probability equals .5).</p>
<p>I also said it was one because P(x>=1)>50% and P(x<=1)>50%, hence it satisfied the conditions given.</p>
<p>cant believe i wrote 2 :l. i panicked! the question was worded so weird, so i just wrote down a random number</p>
<p>for the part d, what did u say? i had no time left, so i said mean is skewed right and median is robust.</p>
<p>i wrote that since the graph is skewed right, it makes sense that the median (1) is lower than the mean (1.6).</p>
<p>I wrote the same as wrathofgod64 and I also added that since it is positively skewed, the distribution's upper tail is longer than its lower tail - just to cover all of my bases.</p>