<p>was the amount of squares 7 to be symmetric over y axis?</p>
<p>Is it possible to -1 and still get a 36…or is that too optimistic for the math curb</p>
<p>Ok, then it was definitely sin^2(θ) - 4 + cos^2(θ) because I remember plugging in a number for theta to check the identity, and the answer has to be -3.</p>
<p>@laptop the math curve is almost always -1/35 
Sometimes it’s -3/34.</p>
<p>@sbl0323: Yay! I remember putting -3 for that one.</p>
<p>I don’t know if this was mentioned before, but for the splitting the cone perpendicular to the base question, was the answer a simple triangle? For me it was between that and a triangle with a semicircle bottom.</p>
<p>@Agg Yes, it was a triangle. If it had a curve at the bottom, the bottom of the cone would’ve been a bulge.</p>
<p>i had a triangle/semicircle which is not right</p>
<p>^LMAOOO. I REMEMBER THAT ONE! With the cone pictures. What. The. ■■■.</p>
<p>ALSO, I just remembered one, for the one with the graph and line of symmetry, it looked something like this: <a href=“http://i54.■■■■■■■.com/1z1wcpd.jpg[/url]”>http://i54.■■■■■■■.com/1z1wcpd.jpg</a></p>
![http://i54.■■■■■■■.com/1z1wcpd.jpg[/url]](http://i54.tinypic.com/1z1wcpd.jpg%5B/url%5D){kind=link}
<p>I THINK I put y =-1/2x</p>
<p>i put y=-x or something</p>
<p><a href=“http://i40.■■■■■■■.com/1zp47zd.jpg[/url]”>http://i40.■■■■■■■.com/1zp47zd.jpg</a> < Cone.</p>
![http://i40.■■■■■■■.com/1zp47zd.jpg[/url]](http://i40.tinypic.com/1zp47zd.jpg%5B/url%5D){kind=link}
<p>@Giancolii
for that grapgh one i think i put x=y…but i kinda guessed</p>
<p>i had y=x or y=-x not sure</p>
<p>Yeah I just guessed and moved on. :\ The graph questions were not my thing.</p>
<p>The graphing transformation was y=x. The line of y=x goes from the bottom left to the top right, while y=-x is the reverse, which is wrong.</p>
<p>i was tight on time and had to use the bathroom so my thinking wasn’t clear
edit: i put y=x i remember now</p>
<p>It’s y=x for sure. Visualize a y=x line (diagonal with slope 1 going through origin) and then reflect the image to that…it was reflected from quadrant II to IV so it had to be y=x.</p>
<p>Mmmmm. :(</p>
<p>Also, for the sinx/cosx graph, the one with the wavy lines (g(x) and f(x)), that question was very simple, yes?</p>
<p>Up 1, right pi/4</p>
<p>up one and pi/4 right i think</p>
<p>I put Quad II and IV, I hope…</p>
<p>i put quads 1 and 2 for the triangle one at the very end</p>