<p>A restaurant has 19 tables that seat 84 people. Some of the tables seat 4 people and some seat 5 people. How many tables seat 5 people?</p>
<p>a. 4
b. 5
c. 6
d. 7
e. 8</p>
<p>A restaurant has 19 tables that seat 84 people. Some of the tables seat 4 people and some seat 5 people. How many tables seat 5 people?</p>
<p>a. 4
b. 5
c. 6
d. 7
e. 8</p>
<p>look through this thread:</p>
<p><a href=“http://talk.collegeconfidential.com/sat-preparation/759703-math-help-center-3.html[/url]”>http://talk.collegeconfidential.com/sat-preparation/759703-math-help-center-3.html</a></p>
<p>You’ll see multiple solutions.</p>
<p>5x+4y=84
x+y=19</p>
<p>Just set up two equations and solve the system.</p>
<p>Or just start trying the answer choices.</p>
<p>
</p>
<p>You have two variables thus you need two equations.
x + y = 19
4x + 6y = 84</p>
<p>However for a question like this I would simply just “plug & chug”.</p>
<p>Pick A,B,C,D, or E. I picked C.
(6*5) + (13 *4) = 84
30 + 52 = 84
82 = 84 (wrong)</p>
<p>I then picked D.
(7<em>5) + (12</em>4) = 84
35 + 48 = 84
83 = 84</p>
<p>I then picked E.
(8<em>5) + (11</em>4)
40 + 44 = 84
84 = 84</p>
<p>thanks everyone!</p>
<p>ugh my math score is a 540,after my first try as a junior. While my CR is 680 and writing 730; I’m so unbalanced!</p>