bb pg 473 #8

<p>Is the only way to solve this problem is by realizing that inside the figure there is a quadrilateral that contains all 3 letters? I would have never realize to acknowledge that all 3 letters are in the quadrilateral.</p>

<p>is there any other way to do this? perhaps maybe a plug in the number method?</p>

<p>thanks.</p>

<p>anybody know?</p>

<p>i would greatly appreciate it.</p>

<p>please write down the problem, because I don't have the bb but I would solve it for you if you do so.</p>

<p>I just looked at the problem, but I have no idea how to get the answer...I see how it uses 2a and 3b and that you would take those from the whole to get c, but I just don't understand the problem really. </p>

<p>Sorry I can't be of much help. Math isn't my strong suit.</p>

<p>All you need for this one is that the sum of the angles in a triangle is 180, and that angles along a line add up to 180.</p>

<p>Moving along the left side of that big triangle, you have three unlabeled angles. The first is 180-a-b , the second is 180-a-b and the third is 180-b-c. These three add up to 180, since we are moving along a line (the left side of the big triangle) ...</p>

<p>thanks fignewton! what a clever method..did you figure out the problem the first time you saw it?</p>

<p>I still don't get it...how does that add up to the answer? ><</p>

<p>180-a-b
180-b-c
180-a-b</p>

<p>add those 3 up and you get 540-2a-3b-c=180</p>

<p>now subtract 180 and make add c to make it positive nad you get c=360-2a-3b</p>

<p>OH~! xD See, I could never figure something like that out by myself...I'm so bad at math. >> I'll probably bomb the SAT math section in a few weeks... :(</p>