<p>If anyone knows how to do this or can offer insight, I would really appreciate it.</p>
<ol>
<li>The pyramid shown above has altitude h and a square base of side m. The four edges that meet at V, the vertex of the pyramid, each have length e. If e = m, what is the value of h in terms of m?</li>
</ol>
<p>Can't reproduce the picture (obviously) but I think the problem gives you all the pertinent information. Also, the answer is m/(square root of 2), if that helps.
Thanks in advance</p>
<p>edit: 2nd edition… oops.</p>
<p>
<a href=“ImageShack - Best place for all of your image hosting and image sharing needs”>ImageShack - Best place for all of your image hosting and image sharing needs
</a></p>
<p>i would like some help on this as well</p>
<p>The square has length m. This means the diagonal is m(rad2). Half the diagonal is m(rad2)/2. Notice that the number i just calculated is one of the legs of the right triangle. The other leg is h, and the hypotenuse is e = m. Then use pythag. theorem.
h^2 + m^2(2/4) = m^2
h^2 + m^2/2 = m^2
h^2 = m^2/2
h = m/(rad2)</p>
<p>oooh. icic thanks</p>
<p>no problem. and thanks for providing the picture by the way.</p>
