<p>Questio number 14 on page 14 there is a diagram
question number 2 (yes im an idiot)
and question number 13</p>
<p>please add page 673 number 18</p>
<p>is it so much to ask for some help?</p>
<p>I'm not sure where your first three questions are located...but for pg 673 - #18</p>
<p>If the sum of the consecutive integers from -22 to x, inclusive, is 72, what is the value of x?
(A) 23
(B) 25
(C) 50
(D) 75
(E) 94</p>
<p>The answer is B. If you had time you could just guess and check in your calculator....but the way I did it:
If you picture a number line, with -22 on the far left and x on the right: since the question calls for the sum, the easy way to do that is just to combine "like" numbers. Therefore you would add -1 with 1, -2 with 2, -3 with 3 so on. On your number line if you connected those "like" numbers with curved lines, you'd begin to form a rainbow :)</p>
<p>So since the sum is positive, you know that x has to be above 22, if x were 22, you'd break even at 0, if x were below 22, you'd have a negative sum. How much higher is x then? Well, 23 + 24 + 25 higher, or 72. Since the series starts at -22, you don't connect 23 with -23, which is technically off of your isolated number line. Therefore, its just pure addition.</p>
<p>That was probably really confusing, but since I posted the problem at least, maybe someone else has a better way of explaining.</p>
<p>oh man well question number 14 on page 656
question 13 on page 683
and question two on page 679</p>
<p>thanks</p>
<p>thanks for that explanation Echelon32 it really did help</p>