<p>Sat test 2
Math section 2
Problems: 18</p>
<p>Math section 5
Problems: 13,17,18, 8</p>
<p>Math section 8
Problems: 12,13,14</p>
<p>Please show all work if u can! Thank you all so much! Got a 630 (first time ever taking it, no prep. Lol i feel good about it, prob horrible to u guys!)</p>
<p>Also if theres a website with worked out solutions that works also. :)</p>
<p>Sct 2, #18 the cylinder in the box.</p>
<p>The diameter of the cylinder will be equal to the width and length of the box. The height will be the same. Therefore, the volume of the box will be d x d x h, or d^2(h)</p>
<p>Sct 5, # 13</p>
<p>First find the decrease by subtracting the two totals at the bottom of the chart. Ave = total/number of things in the group. (in this case, 3) Divide by three. 5250/3=1750</p>
<h1>17 - First you have to translate how much each carrier charges into an algebraic expression. Carrier A = 1 + (t-20) x .07t *don’t forget to subtract the 20 from the time because the first 20 minutes are include in the 1. Carrier B = .06t They ask you when the price will be the same so set these two expressions equal to one another and solve for t.</h1>
<p>1 + (t-20) x .07t = .06t </p>
<h1>18</h1>
<p>The area of one block = k^2
There are 10 blocks, so total area = 10k^2
There are 16 sides around the perimeter, so p=16k
p=a (given)</p>
<p>16k = 10k^2 (substitute)
8 = 5k (divide by 2k)
k = 8/5 (divide by 5)</p>
<p>Thanks! I only need number 13 section 8 now</p>
<p>I would solve that one by picking a number for n say n=2. Then k=12 and 2^n+2 = 16 Plug k=12 into the answer choices and see which gives you 16. Just make sure you check EVERY choice, and never pick 1, especially with exponents.</p>
<p>Good luck and keep working on them. They get easier as you get used to them.</p>
<p>Since you have the BB, you should go to [Welcome</a> to the Official SAT Study Guide Book Owner’s Area](<a href=“SAT Study Guide – SAT Suite | College Board”>SAT Study Guide – SAT Suite | College Board) </p>
<p>Register/log into your acct, then you’ll have access to answer explanations.</p>
<ul>
<li>Algebraic solution for the last one: This is tricky.</li>
</ul>
<p>k = 2^n + 2^(n+1) = 2^n(1 + 2) = 3(2^n). </p>
<p>Dividing each side by 3 we get 2^n = k/3</p>
<p>We now multiply each side of the equation by 2^2 to get </p>
<p>(2^n)(2^2) = (2^2)k/3
2^(n+2) = 4k/3</p>
<p>This is choice (B).</p>
<p>Question: Do you see how the factoring was done in the first equation above? Why were we allowed to pull out 2^n? Why were we left with 1 and 2 respectively? If you were able to do this on your own, then your algebra skills are probably very strong. As a hint to answering these questions, note that 2^(n+1) = (2^n)(2^1) = (2^n)(2).</p>