<p>7) Positive integers x, y, and z satisfy the equations x^(-1/2) = 1/3 and y^z = 16.
If z > y, what is the value of x + z?</p>
<p>A) 5
B) 7
C) 11
D) 13
E) 15</p>
<p>This one sounds confusing T_T
And is x^(-1/2) the same thing as 1/x^2 ?</p>
<p>Zester, searching the thread Consolidated List of Blue Book Math Solutions, 3rd ed. (link: <a href="http://talk.collegeconfidential.com/sat-preparation/339734-consolidated-list-blue-book-math-solutions-3rd-ed.html%5B/url%5D">http://talk.collegeconfidential.com/sat-preparation/339734-consolidated-list-blue-book-math-solutions-3rd-ed.html</a> ) I found that the answer to your question is posted here: <a href="http://talk.collegeconfidential.com/4558334-post4.html%5B/url%5D">http://talk.collegeconfidential.com/4558334-post4.html</a></p>
<p>i am not a student ... but i don't even know what the up arrow thing means (nor can i find it on my keyboard!!!</p>
<p>oops, i found it. see???</p>
<p>^^^^^^^^^^^^</p>
<p>good luck!</p>
<p>Positive integers x, y, and z satisfy the equations x^(-1/2) = 1/3 and y^z = 16.
If z > y, what is the value of x + z?</p>
<p>1/sqrt(x) = 1/3
x = 9
y^z = 16
it can be 16^1, 2^4,4^2
but since z>y is mentioned, we take 2^4
so y = 2
x + y = 9+2 = 11</p>
<p>perhaps you got it but my way of doing this was:
2^4=16 so z=4. Then from the answer choices I subtracted 4 and for choice d) 13-4=9. Then I did 9^-.5 and got .333333</p>
<p>D?</p>
<p>spideyunlimited: it's x+z she is asking for. so the answer is 13</p>
<p>MikeW, the ^ is used to show that the following number is an exponent. So x squared can be typed as x^2. The square root of x is typed as x^(1/2). It's a way to work around the shortcomings of having to type equations.</p>
<p>oh ya indiarubber, thanks for correcting lol, I shouldn't have come online half-asleep lol</p>