<p>Page 738, number 20.</p>
<p>I keep getting A, but the answer is B... why?</p>
<p>Hmm how do u do this problem, can anyone help?</p>
<p>Okay, you have to break this one into parts:</p>
<p>1-To find arc SBT: Because this is a quarter of a circle's circumference, use the circumference formula multiplied by 1/4.</p>
<p>Thus: (1/4)(2)(pi)(6)=3(pi)</p>
<p>2-To find SA and CT:</p>
<p>You can't find these ones separately because you don't know the individual width and length. However, you do know that lengths SR and RT must add up to 12 (because each is the length of one radius). You know that the unshaded portions of each of SR and RT must add up to 8 because they are one length and one width. Thus:</p>
<p>(6)(2)-8=4</p>
<p>3-Length AC must be equal to length RB, and length RB is the radius of the circle, so it is 6. Thus, length AC is 6.</p>
<p>Final Answer: B</p>
<p>10+3(pi)</p>
<p>Good luck tomorrow! I'm hoping to increase my pathetic math score too...</p>
<p>Wow, nice job! Thank you very much for that help!!</p>
<p>Can you help me with pg. 859 # 14 please?</p>