<p>How did you guys find the total amount of cars turning left? did you just integrate the area under the curve?</p>
<p>also did you guys use the washer method or the shell method when the area was revolved around the y-axis?</p>
<p>I used the Shell method for at least 1 area problem, I remember. And yes, to find the total amount of cars turning left you just integrate.</p>
<p>Hey, in one of the FRQs they asked for the "average value" (it might have been in the car question). Was that an instance of using the "average value theorem" or is that like on past tests where it's up to you to decide whether they mean average value or mean value theorem? I remember on past AP's that I practiced with, that they used to denote it: "...find the average (mean) value..." Is that what they meant this year? Did they have a new way of expressing it? Haha... does anyone know what I'm talking about? If you do, please clear that up for me! ;) Thanks in advance.</p>
<p>Yeah you had to use f(b)-f(A)/b-a, and that would have given you 11/20 i think.</p>
<p>wait, i thought we can't discuss FR until tomorrow.</p>
<p>Can you guy post the grading scale for AP Cal. AB?
like how many multiple choice questions do we need to get correct in order to get a 3 or above and how many free-response question do we need to answer correctly?
Do we get partial credit for the free-response. If you don't knoiw the answer is it better to put down random answers or leave it blank?
(maybe you could get like 3 points????)</p>
<p>How do you guy integrate the acceleration if there is no equation and all they gave you was the F(X)?</p>
<p>for the one with the volume...should you get two same volume? instead of using the shell method, could you also put it into terms of x and then use the washer method?</p>
<p>"How do you guy integrate the acceleration if there is no equation and all they gave you was the F(X)?"</p>
<p>Most people at my school didn't know how to do that either, but its a lot easier then it looks.</p>
<p>F[x] was velocity right and they gave you the values from 0-80</p>
<p>All you have to do is take f[80]-f[0]/80 and you get (49-5)/80=11/20 ft/s^2</p>
<p>for the car traffic one you guys took the most area right near the maximum with the 2 hour time span.</p>
<p>however, i did it differently, but still ended up with Yes, it needed a traffic light.i I did it over 18 hours, so 9 intervals. 9x200,000 needed minimum for the traffic light. the area of the curve from 0 to 18 was like 7 million so i said yes, it needed a traffic light. will i still get partial credit?</p>
<p>Well, do you think if I explained what to do but didn't solve it would I get any points.</p>
<p>was it Rocket A or Rocket B, ppl at my school were split? I got B, but think it was A....b/c i didnt account for initial</p>
<p>OOS or bust: idk if you'll get any points...wait until 4 pm tomorrow</p>
<p>eji: i think it was Rocket B.</p>
<p>now I'm nervous about seeing the FRs...now that i think about it i feel as though i did terrible. Hoping for mostly 6s and 7s tho'.</p>
<p>idk y i care, NYU stern doesnt recognize the exam....as credit or placement</p>
<p>im pretty sure it was rocket A cuz what u guys tend to forget is that after integrating u are left with an expression + C the constant....setting this expression + C = to the initial velocity and solving u get a velocity of 48 ft/sec or whatever units which is one less the the 49 in rocket a...concluding that rocket a is faster.</p>
<p>Thank you, I don't how but I did exactly the same thing =11/20</p>
<p>eh, well know about all of them tomorrow...no point in worrying now.</p>
<p>must....study....APUSH</p>
<p>who here got rocket a...im like one of a very few in the nation lol</p>
<p>I was rooting for rocket A, go go go Rocket A! lol </p>
<p>I guess that makes two in the nation.. literally.</p>
<p>lol I didn't, but being the minority, it makes me feel as tho' rocket A people were correct.</p>