<p>arghhh... I did it right, just forgot to cancel cos^2x out... lol</p>
<p>^right, so if you had to find the average value of f'(x) with respect fo f(x), would it be MVT for derivs? </p>
<p>BTW, I really appreciate your help, I honestly do.</p>
<p>I don't think the MVT is related. I apologize if I'm not able to fully understand what you mean.</p>
<p>Let me try to just explain my equation for the average rate of change and maybe you'll see...</p>
<p>Integral of f ' (x) is the change in f in the given period Therefore, dividing that by the change in x gives you:</p>
<p>(change in f)/(change in x).... that is the average rate of change</p>
<p>Mean value theorem is (f(b)-f(a))/ (b-a).........it's a similar equation, maybe that's what's confusing you? Or maybe I'm the one who's wrong.</p>
<p>What the Mean Value Theorem says is that if a function f is differentiable, then a value of c exists on [a, b], such that f '(c) = (f(b) - f(a))/(b-a).</p>
<p>The average rate of change is simply the slope of the secant line, which is (f(b) - f(a))/(b-a).</p>
<p>The average value of f(x) on an interval is 1/(b-a) * integral (from a to b) f(x) dx.</p>
<p>So if they ask for the average value of f '(x), you find 1/(b-a) * integral (from a to b) f '(x) dx, which just so happens to be equal to the average rate of change. If you think about it, that makes sense. It's the "average value" of the "rate of change of f".</p>
<p>Goodnight and Good Luck to fellow AB/BC Takers tomorrow!</p>
<p>yea good luck everyone. I'm going to sleep! lol.</p>
<p>good luck...im still up..i took a 6 hour nap..im prepared to ace this isht......</p>
<p>wait!!!!!!!!!!</p>
<p>last second question...we're allowed to use negative exponents on the free response right???????????/</p>
<p>i imagine so; e^-x is the same thing as 1/(e^x)</p>
<p>i always put it in the latter form, but i don't think it matters</p>
<p>Might be too late for during the fact, but as an after the fact idea, negative exponents are allowed.</p>
<p>Good luck today, everybody.</p>
<p>gosh i stayed all last night...
good luck everyone</p>
<p>Alright, reactions. I thought it was fairly easy, although I still bombed the last two free response :(. Remember, no specifics.</p>
<p>Pretty easy. The FR were good, except the last 2 were a little bit difficult. Part 1 of MC also had some hard ones. But I managed to answer every question, so it couldn't have been too bad.</p>
<p>I still think it was difficult</p>
<p>Part 2... was... so... ridiculous</p>
<p>I actually thought the Non calculator section of the MC Q's were easier than the ones we could use a calculator for .. Overall, I think my grade will really justify my work ethic this year. So I think I deserve a 4, but who knows.</p>
<p>I have mixed opinions about the FRQs .. --;;</p>
<p>I feel like most of you, mixed about the FRQs. I only left 4 blank on the MC for both sections. The MC calculator part was very easy I thought compared to the non calc. </p>
<p>In the FRQ, the #4 (;) think ski fields) was annoying because parts b and c were dependent on each other and b was annoying specifically because of ln and just dealing with a headache and stress.</p>
<p>Although, the last two were also hard, I think I managed to get it right somewhat. I know I missed some minor things for other parts after talking with people, so I can safely assume that I probably missed at least 9 points out of the possible 54 in the FRQ. Hopefully because I think I did farily well on the MC I should get at least a 3. That's all I need anyway :)</p>
<p>I think you're all talking about AB, but if anyone took BC, I thought it was relatively easy.</p>
<p>Time is distributed far too unevenly; I guessed on about 4 of the noncalculator multiple choice and finished the calculator with 25 minutes left, confident I got those all perfectly. </p>
<p>Free response was good as well. Pretty sure I got a 5. Sweeet.</p>
<p>I expected it too be much harder than it turned out to be</p>
<p>The FRQ were RIDICULOUS! I have no idea how i did but thought that non-calculator multiple choice were easier than expected.</p>